我想在某些条件下汇总表中的行。例如,我有:
x <- data.frame("id"=c("T","T","R","R"),"value"=c(10,-5,10,-5),"level"=c(3,2,1,2))
print(x)
我的条件是:对于相同的“ id”,如果负值的水平低于正值的水平,则可以通过求和来求和。所以我得到了:
x <- data.frame("id"=c("T","R","R"),"value"=c(5,10,-5))
print(x)
我可以使用aggregate()功能吗?
答案 0 :(得分:1)
或者:
x <- data.frame("id"=c("T","T","R","R"),"value"=c(10,-5,10,-5),"level"=c(3,2,1,2))
lookup_vec <- setNames(x[sign(x$value) == 1, ]$level,
as.character(x[sign(x$value) == 1, ]$id))
x$level_plus <- lookup_vec[as.character(x$id)]
x$level_plus <- ifelse(x$level_plus >= x$level, x$level_plus, x$level)
aggregate(value ~ id + level_plus, x, sum)[c("id", "value")]
# id value
# 1 R 10
# 2 R -5
# 3 T 5
答案 1 :(得分:0)
您可以使用by
。
do.call(rbind, by(x, x$id, function(x) {i <- cbind(x, d=c(1, diff(x[, 3]))); i[i$d > 0, 1:2]}))
# id value
# 1 T 5
# 2 R 10
# 3 R -5