Question

我有一个清单：

var = ["renderPass1", "renderPass2","renderPass3", "renderPassFilter", "renderPassSets"]

如何只打印renderPass1，renederPass2等，我的意思是，只打印“renderPass”之后包含数字的成员

Answer 1

使用正则表达式查找数字。

查看python库：Python: Re。你想看看“\ d”。

帮助我使用正则表达式的工具是Txt to Regex。您只需输入要匹配的字符串，然后使用GUI构建正则表达式。然后它会为你提供代码。

Answer 2

for value in var:
    if value[-1].isdigit(): # check if last char is a number
         print value

现在，如果你想测试“renderPass”的字符串

  for value in var:
        if 'renderPass' in value and value[-1].isdigit()
             print value

Answer 3

我会给出两个答案，因为你的问题并不清楚什么是匹配。

如果数字的位置与不相关，则为此：

>>> var = ["renderPass1", "renderPass2","renderPass3", "renderPassFilter", "renderPassSets"]
>>> [x for x in var if any(c.isdigit() for c in x)]
['renderPass1', 'renderPass2', 'renderPass3']
>>>

这是因为如果数字必须在"renderPass"之后：

>>> from re import search
>>> # I altered the values in here so I could demonstrate
>>> var = ["renderPass1", "renderPass2","renderPass3", "1renderPassFilter", "1renderPassSets"]
>>> [x for x in var if search("renderPass.*\d", x)]
['renderPass1', 'renderPass2', 'renderPass3']
>>>

Answer 4

假设您只需要带有“SomeTextNumber”的模式，您可以这样写

[x for x in var if re.match("\w+\d$", x)]

Answer 5

选择一个，具体取决于您对列表中的内容了解多少。

先打印3

print var[:3]

打印任何带有模式renderPass后跟数字

的名称

print [name for name in var if name.startswith('renderPass') and name[9].isdigit()]

打印任何位置带有数字的任何名称

print [name for name in var if any(ch.isdigit() for ch in name)]

Answer 6

for name in var:
    try:
        float(name[len("renderPass"):])
        print name
    except ValueError, er:
        # does not have a number after renderPass -> do nothing
        pass

Answer 7

import re
p = re.compile("[0-9]$")
for s in var:
    if p.search(s): print s

Python如何打印包含数字的字符串

7 个答案: