Question

我正在从有序链表（按字母频率排序）构建一个以最低频率开头的霍夫曼编码树。创建树后，我遍历了它，看起来树的实现不正确。当我遍历树时，有序链表中的一些节点似乎被遗漏了。（我不认为这是因为我的遍历是错误的。）这是我的树代码：

//My class for the nodes in the ordered linked list that will be converted to a tree
class fList{
public:
  fList();
  int frequency;
  char letter;
  fList* next;
  fList* left;
  fList* right;
};

fList::fList(){
  frequency = 0;
  letter = NULL;
  next = NULL;
  left = NULL;
  right = NULL;
}
fList* head = NULL;

    .
    .
    .
    .
    .

//Create the huffman encoding tree from the linked list stored in head
while(head->next != NULL){
    fList *tree = new fList();
    fList *temp = new fList();
    fList *trail = new fList();

    /* Take the first two frequency numbers, add them, create a new node                             
     * with the total frequency number and have new node point to the first                          
     * two nodes (right child and left child) 
     */                                                       
    total = (head->frequency + head->next->frequency);
    tree->frequency = total;
    //Set a new head node
    tree->left = head;
    tree->right = head->next;
    head = head->next->next;
    tree->left->next = NULL;
    tree->right->next = NULL;

    //place tree node in its correct place in sorted list                                           
    temp = head;
    trail = temp;
    if(head->frequency >= tree->frequency){
      tree->next = head;
      head = tree;
    }

    else if(temp->next != NULL){
      while(temp != NULL){
        if(temp->frequency >= tree->frequency){
          tree->next = temp;
          trail->next = tree;
          break;
        }
        else{
          trail = temp;
          temp = temp->next;
        }
      }//while                 

    //insert at the end of list                                                                   
    if(temp == NULL){
      temp = tree->next;
      trail->next = tree;
    }
  }//else if !=NULL 

  else if(head == NULL || head->next == NULL) head = tree;
}

Answer 1

在您发布的代码段的末尾，在

行中

else if(temp->next = NULL && head != NULL) head = tree;

您无意中截断了树temp->next = NULL，您可能想问temp->next == NULL。这可能就是为什么有些条目（由temp链接的条目）被遗漏在最终结果中。

从有序列表中构建霍夫曼编码树

1 个答案: