我有下表,但不确定是否可以将其转动并保留所有标签。
RATIO RESULT SCORE GRADE
Current Ratio 1.294 60 Good
Gearing Ratio 0.3384 70 Good
Performance Ratio 0.0427 50 Satisfactory
TOTAL NULL 180 Good
我承认在使用枢轴方面不是很好,所以经过多次尝试后产生了这个输出:
SELECT 'RESULT' AS 'Ratio'
,[Current Ratio] AS 'Current Ratio'
,[Gearing Ratio] AS 'Gearing Ratio'
,[Performance Ratio] AS 'Performance Ratio'
,[TOTAL] AS 'TOTAL'
FROM
(
SELECT RATIO, RESULT
FROM GRAND_TOTALS
) AS SREC
PIVOT
(
MAX(RESULT)
FOR RATIO IN ([Current Ratio],[Gearing Ratio], [Performance Ratio], [TOTAL])
) AS PVT
这给出了结果:
Ratio Current Ratio Gearing Ratio Performance Ratio
Result 1.294 0.3384 0.0427
我承认我对接下来该做什么感到非常难过,以产生我需要的结果:
Ratio Current Ratio Gearing Ratio Performance Ratio TOTAL
Result 1.294 0.3384 0.0427 NULL
Score 60 70 50 180
Grade Good Good Satisfactory Good
答案 0 :(得分:46)
由于您想要转移多列数据,我建议首先对result
,score
和grade
列进行取消隐藏,这样您就没有多列,但是您会有多个列行。
根据您的SQL Server版本,您可以使用UNPIVOT函数或CROSS APPLY。取消数据取消的语法类似于:
select ratio, col, value
from GRAND_TOTALS
cross apply
(
select 'result', cast(result as varchar(10)) union all
select 'score', cast(score as varchar(10)) union all
select 'grade', grade
) c(col, value)
见SQL Fiddle with Demo。一旦数据被取消,您就可以应用PIVOT功能:
select ratio = col,
[current ratio], [gearing ratio], [performance ratio], total
from
(
select ratio, col, value
from GRAND_TOTALS
cross apply
(
select 'result', cast(result as varchar(10)) union all
select 'score', cast(score as varchar(10)) union all
select 'grade', grade
) c(col, value)
) d
pivot
(
max(value)
for ratio in ([current ratio], [gearing ratio], [performance ratio], total)
) piv;
见SQL Fiddle with Demo。这将给你结果:
| RATIO | CURRENT RATIO | GEARING RATIO | PERFORMANCE RATIO | TOTAL |
|--------|---------------|---------------|-------------------|-----------|
| grade | Good | Good | Satisfactory | Good |
| result | 1.29400 | 0.33840 | 0.04270 | (null) |
| score | 60.00000 | 70.00000 | 50.00000 | 180.00000 |