我已经完成了结果集的读取,并使用Java Servlet和jtds驱动程序在SQL Server数据库的ListFragment
上显示它。这是使用JSON完成的。
现在请指导我如何使用JSON进行Insert \ Delete \ Update操作。
由于
答案 0 :(得分:0)
我通过以下代码实现了此目的,并使用JSON
解析了JSONParser
。
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("my_url");
List parameters = new ArrayList(2);
JSONObject jsonObject = new JSONObject();
jsonObject.put("par_1", "1");
jsonObject.put("par_2", "2");
jsonObject.put("par_3", "3");
parameters.add(new BasicNameValuePair("action", "par_action"));
parameters.add(new BasicNameValuePair("data", jsonObject.toString()));
httpPost.setEntity(new UrlEncodedFormEntity(parameters));
HttpResponse httpResponse = httpClient.execute(httpPost);
Log.v("Server Application", EntityUtils.toString(httpResponse.getEntity())+" "+jsonObject.toString());
} catch (UnsupportedEncodingException e) {
Log.e("Server Application", "Error: " + e);
} catch (ClientProtocolException e) {
Log.e("Server Application", "Error: " + e);
} catch (IOException e) {
Log.e("Server Application", "Error: " + e);
} catch (JSONException e) {
e.printStackTrace();
}