Question

所以我必须做三个功能。一个问一个公司有多少员工。另一个问他们错过了多少天。第三个通过将员工数除以缺失的天数来计算平均值。在主要方面，我所要做的就是有cout提示并调用函数。我不确定我是否做得对，但是当它必须计算平均值时会崩溃。

#include <iostream>
#include <iomanip>
using namespace std;

int employee(int employeeNum);
int missingDays(int daysMissing);
double getAvg(int employeeNum,int daysMissing,double average);

int employee(int employeeNum)
{
  cout<<"Enter the number of employee in the company.";
  cin>>employeeNum;
  return employeeNum;
}

int missingDays(int daysMissing)
{
  cout<<"Enter the amount of days employees missed during the past year.";
  cin>>daysMissing;
  return daysMissing;
}

double getAvg(int employeeNum,int daysMissing,double average)
{
  average=employeeNum/daysMissing;
  return average;
}

int main()
{
  int employeeNum,people,missing,daysMissing;
  double avg,average;

  people=employee(employeeNum);
  cout<<"The number of employees in the company is "<<people<<"."<<endl;

  missing=missingDays(daysMissing);
  cout<<"The number of days employees missed during the past year is "<<missing<<".";

  avg=getAvg(employeeNum,daysMissing,average);
  cout<<average;
}

让我知道我要做什么，并感谢你的帮助。

Answer 1

这看起来像是家庭作业，所以你应该只期待轻推。所以，一些推动：为什么你的函数employee()和missingDays()会得到参数？为什么getAvg()需要3？您的输入值最终会在哪些变量中出现？它们在哪里使用（如果有的话）？

Answer 2

你的问题就在这一行

missing=missingDays(daysMissing);

由于某种原因，你有两个“daysMissing”变量（我不知道为什么你首先将它传递给你的missingDays函数）

在该行之后，missing将包含值输入，而不是daysMissing（因为它未通过引用传递）

你的getAvg函数可能会因为零错误而崩溃。

Answer 3

因此，根据编译器，daysMissing的值未定义或使用0进行初始化。

在您的函数getAvg中划分employeeNum/daysMissing;

但是你不能被零除，这就是它：）

Answer 4

#include <iostream>
#include <iomanip>
using namespace std;

int employee(int employeeNum);
int missingDays(int daysMissing);
double getAvg(int employeeNum,int daysMissing,double average);

int employee(int employeeNum)
{
  cout<<"Enter the number of employee in the company: ";
  cin>>employeeNum;
  return employeeNum;
}

int missingDays(int daysMissing)
{
  cout<<"Enter the amount of days employees missed during the past year: ";
  cin>>daysMissing;
  return daysMissing;
}

double getAvg(int employeeNum,int daysMissing)
{
    if(daysMissing == 0)
    {
        return 0;
    }
  return (double)employeeNum/daysMissing;;
}

int main()
{
  int employeeNum,people,missing,daysMissing;
  double avg,average;

  people=employee(employeeNum);
  cout<<"The number of employees in the company is: "<<people<<"\n";

  missing=missingDays(daysMissing);
  cout<<"The number of days employees missed during the past year is: "<<missing<<"\n";

  avg=getAvg(people,missing);
  cout<<avg;
}

在c ++中调用函数时，我的程序崩溃了

4 个答案: