Question

通过将下面的TeamRecords = 1更改为=另一个数字来查找具有我更改的数量的行，它有时仅计数太多，这是奇数。创建新事件时，它具有唯一编号，每次从任务表添加新分配时，它会添加IncidentNumber的另一行，因此您可以使用下面的seq = 1删除重复的事件编号行。当创建新的赋值时，它会在Task表中创建一个新的CreateddateTime，例如你可以执行Max（t。[CreatedDateTime]来查找任何IncidentNumber的最后一个赋值。所以，TeamRecords = 1是我需要找到的该特定团队的所有记录，其中该团队只有1个任务。

这对你有帮助吗？这是我到目前为止所拥有的......

Use TEST
Go

  WITH RankResult AS
(   
SELECT  i.[IncidentNumber],
        i.[CreatedDateTime],
        i.[ResolutionDateAndTime],
        i.[Priority],
        i.[Status],
        i.[ClientName],
        i.[ClientSite],
        t.[OwnerTeam],
        t.[Owner],
            row_number() over( partition by i.RecID 
                        order by t.CreatedDateTime desc, t.OwnerTeam ) seq,
        TeamRecords = COUNT(*) OVER(PARTITION BY t.ParentLink_RecID)
FROM    Incident as i
        Inner JOIN Task as t
            ON i.RecID = t.ParentLink_RecID
WHERE   t.OwnerTeam = 'Infrastructure Services'
AND     i.CreatedDateTime >= '20121001'
AND     i.CreatedDateTime <= '20131001'

)
SELECT  DISTINCT
    [IncidentNumber],
    [CreatedDateTime],
    [ResolutionDateAndTime],
    [Priority],
    [Status],
    [ClientName],
    [ClientSite],
    [OwnerTeam],
    [Owner]
FROM    RankResult
Where   TeamRecords = 1
And Seq = 1
Order By IncidentNumber Asc
GO

Answer 1

您始终可以使用一个简单的子查询，该子查询在相关列中进行分组，计算它们，计数为1的过滤器，然后将其连接回主表以选择适当的行：

SELECT      Incident.*
FROM        (
                SELECT      OwnerTeam
                FROM        Incident AS Inc1
                GROUP BY    OwnerTeam
                HAVING      COUNT( * ) = 1
            )   AS Team 
        ,   Incident
WHERE       Incident.OwnerTeam = Team.OwnerTeam

（但是，如果没有更多信息，很难说这是否适合您。）

Answer 2

使用ROW_NUMBER意味着您将返回每个团队的第一个作业，而不一定只有一个作业的团队。为此，您可以使用COUNT(*) OVER()：

WITH RankResult AS
(   
    SELECT  i.[IncidentNumber],
            i.[CreatedDateTime],
            i.[ResolutionDateAndTime],
            i.[Priority],
            i.[Status],
            i.[ClientName],
            i.[ClientSite],
            t.[OwnerTeam],
            t.[Owner],
            TeamRecords = COUNT(*) OVER(PARTITION BY i.RecID)
    FROM    Incident as i
            INNER JOIN Task as t
                ON i.RecID = t.ParentLink_RecID
    WHERE   t.OwnerTeam = 'Info Services'
    AND     i.CreatedDateTime >= '20121001'
    AND     i.CreatedDateTime <= '20131001'

)
SELECT  DISTINCT
        [IncidentNumber],
        [CreatedDateTime],
        [ResolutionDateAndTime],
        [Priority],
        [Status],
        [ClientName],
        [ClientSite],
        [OwnerTeam],
        [Owner]
FROM    RankResult
WHERE   TeamRecords = 1;

要注意的是，除了分析功能之外，我已经改变了两件事。首先，我已将您的日期更改为与文化无关的格式yyyyMMdd，yyyy-MM-dd仍然可能不明确，因此2013-01-02可能是2月1日或1月1日，具体取决于您的服务器/会话设置。其次，无论如何，你的cluase将你的联接转变为INNER JOIN，所以我只是把它变成INNER JOIN：

    FROM    Incident as i
            LEFT JOIN Task as t
                ON i.RecID = t.ParentLink_RecID
    WHERE   t.OwnerTeam = 'Info Services'
    AND     i.CreatedDateTime >= '20121001'

此处，如果Task中没有匹配，则OwnerTeam将NULL且NULL = 'Info Services'的评估结果为false，因此您永远不会返回任何匹配的行Task因此使其成为内部联接。如果你确实想要LEFT JOIN，那么你需要将这个子句移动到JOIN：

    FROM    Incident as i
            LEFT JOIN Task as t
                ON i.RecID = t.ParentLink_RecID
                AND t.OwnerTeam = 'Info Services'
    WHERE   i.CreatedDateTime >= '20121001'

显示团队分配= 1的记录

2 个答案: