我正在尝试制作一个简单的图表应用程序,我偶然发现了一个问题。我有一个点数组,代表一个45度线(y = x)100点。然后,我尝试通过将每个点的值转换为其像素值来绘制线条,然后使用graphic.DrawLines()
从一个点到另一个点绘制线条。
基本代码:
struct MyPoint
{
double X { set; get; }
double Y { set; get; }
}
List<MyPoint> Values;
List<System.Drawing.Point> Points;
for (int i = 0; i < Values.Count; i++)
{
// convert point value to pixel coordinate
int x = (int)((Values[i].X - MinimumX) * (double)Control.Width / (MaximumX - MinimumX) + 0.5);
int y = (int)((Values[i].Y - MinimumY) * (double)Control.Height / (MaximumY - MinimumY)) + 0.5;
Points.Add(new System.Drawing.Point(x, y));
}
graphic.DrawLines(pen, Points.ToArray());
注意:MaximumX和MaximumY为100(点数),最小值为0.
问题是这种线条不是很直接:)所以我的问题是,我如何通过这些点绘制一条直线,这样看起来就像
一样graphic.DrawLine(pen, 0, 0, Control.Width-1, Control.Height-1);
提前致谢!
答案 0 :(得分:2)
由于你正在做一个图形,我有一个基本框架来在控件中拟合值,如下例所示:
public struct MyPoint
{
public double X { set; get; }
public double Y { set; get; }
public PointF ToPoint()
{
return new PointF((float)X, (float)Y);
}
}
/// <summary>
/// For http://stackoverflow.com/questions/19459519/drawing-a-straight-line-from-points
/// </summary>
public partial class Form1 : Form
{
List<MyPoint> points;
public Form1()
{
InitializeComponent();
// Initialize points to draw
points=new List<MyPoint>(100);
for (int i=0; i<=100; i++)
{
double θ=2*Math.PI*(i/100.0);
double x=(1+θ/Math.PI)*Math.Cos(θ);
double y=(1+θ/Math.PI)*Math.Sin(θ);
points.Add(new MyPoint() { X=x, Y=y });
}
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
// smooth graphics
e.Graphics.SmoothingMode=SmoothingMode.AntiAlias;
// set margins inside the control client area in pixels
var margin=new System.Drawing.Printing.Margins(16, 16, 16, 16);
// set the domain of (x,y) values
var range=new RectangleF(-3, -3, 6, 6);
// scale graphics
ScaleGraphics(e.Graphics, pictureBox1, range, margin);
// convert points to pixels
PointF[] pixels=points.Select((v) => v.ToPoint()).ToArray();
// draw arrow axes
using (var pen=new Pen(Color.Black, 0))
{
pen.EndCap=System.Drawing.Drawing2D.LineCap.ArrowAnchor;
e.Graphics.DrawLine(pen, range.Left, 0.0f, range.Right, 0.0f);
e.Graphics.DrawLine(pen, 0.0f, range.Top, 0.0f, range.Bottom);
}
// draw bounding rectangle (on margin)
using (var pen=new Pen(Color.LightGray, 0))
{
pen.DashStyle=DashStyle.Dash;
e.Graphics.DrawRectangle(pen, Rectangle.Round(range));
}
// draw curve
using (var pen = new Pen(Color.Blue, 0))
{
//e.Graphics.DrawLines(pen, pixels);
e.Graphics.DrawCurve(pen, pixels);
}
}
/// <summary>
/// Scales the Graphics to fit a Control, given a domain of x,y values and side margins in pixels
/// </summary>
/// <param name="g">The Graphics object</param>
/// <param name="control">The Control</param>
/// <param name="domain">The value domain</param>
/// <param name="margin">The margin</param>
void ScaleGraphics(Graphics g, Control control, RectangleF domain, Margins margin)
{
// Find the drawable area in pixels (control-margins)
int W=control.Width-margin.Left-margin.Right;
int H=control.Height-margin.Bottom-margin.Top;
// Ensure drawable area is at least 1 pixel wide
W=Math.Max(1, W);
H=Math.Max(1, H);
// Find the origin (0,0) in pixels
float OX=margin.Left-W*(domain.Left/domain.Width);
float OY=margin.Top+H*(1+domain.Top/domain.Height);
// Find the scale to fit the control
float SX=W/domain.Width;
float SY=H/domain.Height;
// Transform the Graphics
g.TranslateTransform(OX, OY);
g.ScaleTransform(SX, -SY);
}
private void pictureBox1_SizeChanged(object sender, EventArgs e)
{
// redraw on resize
pictureBox1.Refresh();
}
}
答案 1 :(得分:1)
我认为问题是因为你的积分是整数。精确度丢失了。
尝试使用
float x = (float)((Values[i] ...
List<System.Drawing.PointF> PointFs;
而不是
int x = (int)((Values[i] ...
List<System.Drawing.Point> Points;
答案 2 :(得分:0)
你可能需要这样的东西:
private void DrawLine()
{
int xInitial = 0, yInitial = 0, xFinal = Control.Width - 1, yFinal = Control.Height - 1;
int dx = xFinal - xInitial, dy = yFinal - yInitial, steps, k, xf, yf;
float xIncrement, yIncrement, x = xInitial, y = yInitial;
if (Math.Abs(dx) > Math.Abs(dy))
steps = Math.Abs(dx);
else
steps = Math.Abs(dy);
xIncrement = dx / (float)steps;
yIncrement = dy / (float)steps;
for (k = 0; k < steps; k++)
{
x += xIncrement;
xf = (int)x;
y += yIncrement;
yf = (int)y;
Points.Add(new System.Drawing.Point(xf, yf));
}
graphic.DrawLines(pen, Points.ToArray());
}
有关详细信息,请参阅: Bresenham's line algorithm
如果您的点已经通过算法正确计算,而不是简单:
int x = (int) Values[i].X;
int y = (int) Values[i].Y;
应该够了。
答案 3 :(得分:0)
这是我的解决方案:
System.Drawing.Pen myPen;
myPen = new System.Drawing.Pen(System.Drawing.Color.Red);
System.Drawing.Graphics formGraphics = this.CreateGraphics();
formGraphics.DrawLine(myPen, 0, 0, 200, 200);
myPen.Dispose();
formGraphics.Dispose();