我正试图在这个地铁系统中打印出640条路径。我知道有640条路径,因为我已经使用邻接矩阵完成了这个程序。现在我需要用类来做。第一站从'a'开始,路径在站'l'结束。我无法实现递归函数SearchRoute,因为我需要打印路径,标记路径,然后再次标记路径以允许回溯。目前我只能打印'a'到'b'的曲目,因此我的递归函数出现严重错误。任何建议将不胜感激
标题
//Function Declarations
#include <iostream>
#include <string>
using namespace std;
#ifndef SUBWAY_H
#define SUBWAY_H
class Track
{
public:
//Default Constructor
Track();
//Overload Constructor
Track(char, char);
//Destructor
~Track();
//Member variables
char node_1;
char node_2;
bool visited;
};
class Station
{
public:
//Default Constructor
Station();
//Destructor
~Station();
//Overload Constructor
Station(char, int, int);
//Member variables
char station_name;
int track_starting_ID;
int track_size;
};
class SubwaySystem
{
public:
//Default Constructor
SubwaySystem();
//Destructor
~SubwaySystem();
//Recursive function
void SearchRoute(int);
//Other member functions
friend ostream& operator<<(ostream& os, const Track& my_track);
friend ostream& operator<<(ostream& os, const Station& my_station);
//Member variables
Track my_track[34];
Station my_station[12];
int count_routes;
int Current_Station_ID;
//String to save found route
};
#endif
CPP
//Function Definitions
#include <iostream>
#include <string>
#include "subway.h"
using namespace std;
Track::Track()
{
visited = 0;
}
Track::~Track(){
}
Track::Track(char pass_track1, char pass_track2)
{
node_1 = pass_track1;
node_2 = pass_track2;
}
Station::Station(){
}
Station::~Station(){
}
Station::Station(char pass_station_name, int pass_start, int pass_size){
station_name = pass_station_name;
track_starting_ID = pass_start;
track_size = pass_size;
}
SubwaySystem::SubwaySystem()
{
//Initialize tracks
//node_1, node_2
my_track[0] = Track('a', 'b');
my_track[1] = Track('b', 'a');
my_track[2] = Track('b', 'c');
my_track[3] = Track('b', 'd');
my_track[4] = Track('b', 'e');
my_track[5] = Track('b', 'f');
my_track[6] = Track('c', 'b');
my_track[7] = Track('c', 'e');
my_track[8] = Track('d', 'b');
my_track[9] = Track('d', 'e');
my_track[10] = Track('e', 'b');
my_track[11] = Track('e', 'c');
my_track[12] = Track('e', 'd');
my_track[13] = Track('e', 'g');
my_track[14] = Track('e', 'h');
my_track[15] = Track('f', 'b');
my_track[16] = Track('f', 'h');
my_track[17] = Track('g', 'e');
my_track[18] = Track('g', 'k');
my_track[19] = Track('h', 'e');
my_track[20] = Track('h', 'f');
my_track[21] = Track('h', 'i');
my_track[22] = Track('h', 'j');
my_track[23] = Track('h', 'k');
my_track[24] = Track('i', 'h');
my_track[25] = Track('i', 'k');
my_track[26] = Track('j', 'h');
my_track[27] = Track('j', 'k');
my_track[28] = Track('k', 'g');
my_track[29] = Track('k', 'h');
my_track[30] = Track('k', 'i');
my_track[31] = Track('k', 'j');
my_track[32] = Track('k', 'l');
my_track[33] = Track('l', 'k');
//Initialize stations
//station_name, track_starting_ID, track_size
my_station[0] = Station ('a', 0, 1);
my_station[1] = Station ('b', 1, 5);
my_station[2] = Station ('c', 6, 2);
my_station[3] = Station ('d', 8, 2);
my_station[4] = Station ('e', 10, 5);
my_station[5] = Station ('f', 15, 2);
my_station[6] = Station ('g', 17, 2);
my_station[7] = Station ('h', 19, 5);
my_station[8] = Station ('i', 24, 2);
my_station[9] = Station ('j', 26, 2);
my_station[10] = Station ('k', 28, 5);
my_station[11] = Station ('l', 33, 1);
//Initiaize other members
count_routes = 0;
Current_Station_ID = 0;
}
SubwaySystem::~SubwaySystem()
{
}
ostream& operator<<(ostream& os, const Track& my_track)
{
os << my_track.node_1 << '.' << my_track.node_2;
return os;
}
ostream& operator<<(ostream& os, const Station& my_station)
{
os << my_station.station_name << '.' << my_station.track_starting_ID << '.' << my_station.track_size;
return os;
}
void SubwaySystem::SearchRoute(int Current_Station_ID)
{
while (Current_Station_ID < 33)
{
if (Current_Station_ID == 0) //Find a successful route to Station L
{
count_routes++; //Add 1 into the variable “count_routes”
cout << count_routes << " " << my_track[Current_Station_ID] << endl; //Print out this route
return;
}
else //Get into recursive Function Body
{
for (int i = my_station[Current_Station_ID].track_starting_ID; i < my_station[Current_Station_ID].track_starting_ID + my_station[Current_Station_ID].track_size; i++)
{
if (my_track[Current_Station_ID].visited == 0) //if this track is not visited before
{
my_track[Current_Station_ID].visited = 1; //mark this track as visited
my_track[Current_Station_ID].node_2 = 1; //mark its corresponding track as visited
cout << my_track[Current_Station_ID] << endl; //save this track
SearchRoute(Current_Station_ID + 1); //Recursive
i--; //Backtrack this track
my_track[Current_Station_ID].visited = 0;//mark this track as unvisited
my_track[Current_Station_ID].node_2 = 0;//mark its corresponding track as unvisited
}
}
}
}
}
主要
#include <iostream>
#include <string>
#include "subway.h"
using namespace std;
int main(int argc, char **argv)
{
SubwaySystem Test;
Test.SearchRoute(0);
}
答案 0 :(得分:0)
为什么
中有返回声明 if (Current_Station_ID == 0) //Find a successful route to Station L
{
count_routes++; //Add 1 into the variable “count_routes”
cout << count_routes << " " << my_track[Current_Station_ID] << endl; //Print out this route
return;
}
(可能只值得评论,但我讨厌在评论中粘贴代码)
答案 1 :(得分:0)
到目前为止,我可以看到你没有初始化构造函数中的所有成员。至少在赛道上。正确的ctor看起来像:
Track::Track(char pass_track1, char pass_track2)
{
node_1 = pass_track1;
node_2 = pass_track2;
visited = false; // this was missing
}
在C ++中,您必须初始化所有构造函数中的所有成员。否则,值具有以前在内存中的值。访问成员中存在0的可能性是1:2 ^ 32 =&gt;接近于零。
答案 2 :(得分:0)
你好@ace:就像弗兰克建议你需要初始化所有变量一样。但是我还会包含一个默认构造函数,它可以创建单件轨道并使用重载的构造函数:
Track::Track() { Track("~","~"); }
Track::Track(char pass_track1, char pass_track2)
{
node_1 = pass_track1;
node_2 = pass_track2;
visited = false;
}
这意味着基本构造函数将始终从“〜”到“〜”(可以是任何字符)创建单个片段轨道我还将使用基本构造函数的字符,您将不会在实际使用中使用该字符您可以在将来跟踪和跟踪问题,当默认构造函数一目了然时,它就变得明显,因为它包含您选择的所述字符。