Question

我的代码可能出现什么问题？相反，我得到......解析错误：语法错误，意外';'

这是我的示例代码，请你协助我

<form enctype="multipart/form-data" method="POST" action="" > 
    <input type="file" name="file" /><br />
    <input type="submit" value="upload csv" name"submit"/>
</form>

<?php

    $connection = mysql_connect("localhost","root","")
    or die ("Couldn't connect to server");

    $db = mysql_select_db("demo", $connection)
    or die ("Couldn't select database");

    if(isset($_POST['submit']))
    {
        $file = $_FILES['file']['tmp_name'];
        $handle = fopen($file,"r");
        while(($fileop = fgetcsv($handle,1000,",")) !== FALSE)
        $firstname = $fileop[0];
        $lastname = $fileop[1];
        $email = $fileop[2];

        $sql= mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')";
    }

    if($sql)
    {
        echo "Hello from PHP.";
    }
    }

?>

Answer 1

你的PHP中有一个额外的支撑：

if($sql)
{
    echo "Hello from PHP.";
}
} // remove this

此外，您的SQL查询缺少右括号，应该是：

$sql= mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')");

您收到的语法错误是由于特别是sql查询问题 - 它应该是一个右括号，但却找到了一个分号。

您还应该考虑将if ($sql)逻辑移到if (isset($_POST['submit']))块中，因为它只能在该范围内发生。这也可能解决你在Shankar回答的评论中提到的“未定义变量”问题。

还有一点注意......看起来你的while循环只是循环遍历$firstname = $fileop[0];行，因为你没有围绕其余逻辑的大括号。你想要这样的东西吗？

if(isset($_POST['submit']))
{
    $file = $_FILES['file']['tmp_name'];
    $handle = fopen($file,"r");

    $processed = false;
    while(($fileop = fgetcsv($handle,1000,",")) !== FALSE)
    {
        $firstname = $fileop[0];
        $lastname = $fileop[1];
        $email = $fileop[2];

        $sql = mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')");

        $processed = true;
    }

    if($processed)
    {
        echo "CSV was processed.";
    }
    else
    {
        echo "CSV was not processed.";
    }
}
else
{
    echo "Submission was not found.";
}

Answer 2

这里还有一个额外的支撑

if($sql)

{
    echo "Hello from PHP.";

} // here..... remove it
}

并将您的mysql_query语句更改为

 $sql= mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')");

Answer 3

你的问题在于：

$sql= mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')";

这还没有正确关闭。它应该看起来像这样（你错过了结束括号）：

$sql= mysql_query("INSERT INTO test (first_name,last_name,email)values('$firstname','$lastname','$email')");

上传csv逗号分隔成mysql解析错误：

3 个答案: