Question

以下是我尝试使用的片段着色器代码（在OpenGL ES 2.0中，OpenGLES GLSL ES 1.00）：

GLchar strFragmentShader[] =  
"precision mediump float;                                              \n"
"varying vec2 vTexCoord;                                               \n"
"uniform sampler2D sTexture;                                           \n"
"uniform float offset[] = float[]( 0.0000, 1.3846, 3.2307);            \n"
"uniform float weight[] = float[]( 0.2270, 0.3162, 0.0702);            \n"
"void main()                                                           \n"
"{                                                                     \n"
"  vec4 sum = texture2D( sTexture, vec2(vTexCoord)/1024.0)*weight[0];  \n"
"  for (int i=0;i<3;i++) {                                                                 \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord+vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord-vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"  }                                                                                       \n"  
"  gl_FragColor = sum;                                                 \n"
"}                                                                     \n";

我基本上是关注this page上的示例，但我得到ERROR:LEX/PARSE-1 (fragment shader, line 4) Syntax error。

如果我尝试将它们声明为const而不是uniform，建议here（在数组构造函数下），我会得到ERROR:CUSTOM-5 (fragment shader, line 4) Array cannot be const。

显然第4和第5行会遇到同样的问题。如何编译？什么是正确的语法？

Answer 1

我会这样做：

GLchar strFragmentShader[] =  
"precision mediump float;                                              \n"
"varying vec2 vTexCoord;                                               \n"
"uniform sampler2D sTexture;                                           \n"
"void main()                                                           \n"
"{ 
"   vec3 offset = vec3(0.0000, 1.3846, 3.2307);            \n"
"   vec3 weight = vec3( 0.2270, 0.3162, 0.0702);            \n"                                                                    \n"
"  vec4 sum = texture2D( sTexture, vec2(vTexCoord)/1024.0)*weight[0];  \n"
"  for (int i=0;i<3;i++) {                                                                 \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord+vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord-vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"  }                                                                                       \n"  
"  gl_FragColor = sum;                                                 \n"
"}"

或者如果你需要它作为制服传递到着色器：

GLchar strFragmentShader[] =  
"precision mediump float;                                              \n"
"varying vec2 vTexCoord;                                               \n"
"uniform sampler2D sTexture;                                           \n"
"uniform vec3 offset;                                                    \n"
"uniform  vec3 weight;                                                  \n" 
"void main()                                                           \n"
"{                                                                    \n"
"  vec4 sum = texture2D( sTexture, vec2(vTexCoord)/1024.0)*weight[0];  \n"
"  for (int i=0;i<3;i++) {                                                                 \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord+vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"    sum += texture2D( sTexture, ( vec2(vTexCoord-vec2(0.0,offset[i])/1024.0 )*weight[i];  \n"
"  }                                                                                       \n"  
"  gl_FragColor = sum;                                                 \n"
"}"

或使用uniform float[n]如果你需要一个数组，那么n是第二个例子中所需的（常量）大小，如果你需要一个数组，你可以使用第一个例子中的const float[n]不想传递C ++代码中的值。

Answer 2

原来这只是GLES的限制。它无法完成。需要找到另一种方法。

如何在OpenGL片段着色器中分配数组？

2 个答案: