Question

我正在尝试编写一些带字符串的代码并将其翻译成这样; 1.取第一个字母，并将其放在每个单词的单词末尾 2.找到第一个元音并再放一个'b'然后再放元音 3.除最后一个元音

外，与＃2相同

我想我有点接近，但我的输出是所有数字。它甚至看起来都不像存储地址我希望这可以帮助其他人，因为他们可能在return语句中打印数组列表时遇到同样的问题。顺便说一句，这是一个巨大的代码块...抱歉。我这样做的唯一原因是我没有把这两个课程放在这里。

以下是代码：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Experiment {
    public static void main(String[] args){
        String pre = "For every minute you are angry you loose sixty seconds of happiness.";

        System.out.println(translate(pre));
    }

    public static String translate(String sentence){
        String[] sentenceArray = sentence.split(" ");
        List<String> sentenceList = new ArrayList<>();
        List<String> finalList = new ArrayList<>();
        String punctuation = getPunctuation(sentenceArray[sentenceArray.length - 1]);
//add all words but the last so i can take punctuation off it
        for (int i = 0; i < sentenceArray.length - 1; i ++){
            sentenceList.add(sentenceArray[i]);
        }
//take the first letter off each word and put at at the end of each word
        Arrays.asList(sentenceArray);
        for (String el : sentenceArray)
            sentenceList.add(firstToLast(el));
    //use the addFrontB method on each word     
        Arrays.asList(sentenceList);
        for (String la : sentenceList){
            finalList.add(addFrontB(la));
        }
//use the addBackB method on each word
        Arrays.asList(sentenceList);
        for (String le : sentenceList){
            finalList.add(addBackB(le));
        }
        return finalList + punctuation + "\n";
    }
//finds the last character of the last word which is punctuation
    public static String getPunctuation(String word){
        return word.charAt(word.length() - 1) + "";
    }
//takes the punctuation off
    public static String removePunctuation(String word){
        String newWord;
        newWord = word.substring(word.length(), word.length());
        return newWord;
    }
//puts the first letter at the end of the word
    public static String firstToLast(String word){
        char letter = word.charAt(0);
        String newWord = word.substring(1,word.length()) + letter;
        return newWord;
    }
//insterts a b and then the same vowel behind the first vowel
    public static String addFrontB(String word){
        StringBuilder finishedWord = new StringBuilder();

        for (int i = 0; i < word.length(); i ++){
            if (word.charAt(i) == 'a')
                finishedWord = finishedWord.append(word.charAt(i) + 'b' + word.charAt(i));
            else if (word.charAt(i) == 'e')
                finishedWord = finishedWord.append(word.charAt(i) + 'b' + word.charAt(i));
            else if (word.charAt(i) == 'i')
                finishedWord = finishedWord.append(word.charAt(i) + 'b' + word.charAt(i));
            else if (word.charAt(i) == 'o')
                finishedWord = finishedWord.append(word.charAt(i) + 'b' + word.charAt(i));
            else if (word.charAt(i) == 'u')
                finishedWord = finishedWord.append(word.charAt(i) + 'b' + word.charAt(i));
            }
        String newWord = finishedWord.toString();
        return newWord;

    }
//does the same as addFirstB but at the end of the word
    public static String addBackB(String word){
        StringBuilder finishedWord = new StringBuilder();
        finishedWord.append(word);
        finishedWord.reverse();
        for (int i = 0; i < word.length(); i ++){
            if (finishedWord.charAt(i) == 'a')
                finishedWord.append(finishedWord.charAt(i) + 'b').reverse();
            else if (finishedWord.charAt(i) == 'e')
                finishedWord.append(finishedWord.charAt(i) + 'b').reverse();
            else if (finishedWord.charAt(i) == 'i')
                finishedWord.append(finishedWord.charAt(i) + 'b').reverse();
            else if (finishedWord.charAt(i) == 'o')
                finishedWord.append(finishedWord.charAt(i) + 'b').reverse();
            else if (finishedWord.charAt(i) == 'u')
                finishedWord.append(finishedWord.charAt(i) + 'b').reverse();
        }       
        return finishedWord.toString();
    }
}

Answer 1

    return finalList + punctuation + "\n";

您正在将List视为此处的字符串。您是否需要执行.toString()或类似的事情？

asList(T... a)
Returns a fixed-size list backed by the specified array.

您还没有使用Arrays.asList

的返回值

Answer 2

你的错误在这里：

return finalList + punctuation + "\n";

由于你使用plus运算符添加“\ n”，java会调用列表的toString（）方法，这会返回废话。您必须遍历列表并构建自己的字符串，最佳做法是使用StringBuffers。

我的ArrayList只是打印数字

2 个答案: