计算满足Python条件的所有条件

Question

有没有办法在速记嵌套循环中添加满足条件的所有内容？我的以下尝试没有成功：

count += 1 if n == fresh for n in buckets['actual'][e] else 0

Answer 1

将sum与生成器表达式一起使用：

sum(n == fresh for n in buckets['actual'][e])

为True == 1和False == 0，因此不需要else。

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相关内容：Is it Pythonic to use bools as ints? ，Is False == 0 and True == 1 in Python an implementation detail or is it guaranteed by the language?

Answer 2

使用sum()功能：

sum(1 if n == fresh else 0  for n in buckets['actual'][e])

或：

sum(1 for n in buckets['actual'][e] if n == fresh)