我在数据库中有多个表:
tblOjt
ID studentid courseid companyid addresseeid dateadded datestarted dateended ojthours
1 3 1 1 1 9/25/2013 500
tblStudent
ID lastname firstname middlename course gender renderedhours dateadded archive
3 Dela Cruz Juan Santos BSIT Male 500
tblCourse
ID coursealias coursename hours
1 BSIT Bachelor of Science in Information Technology 500
tblCompany
ID companyname
1 MyCompany
tblAddressee
ID addresseename
1 John dela Cruz
我需要一个SQL语句,我可以在其中获取此值:
tableOjt.id tableOJT.surname,firstname, and middlename course companyname addresseename dateadded datestarted dateended ojthours
如何使用这些连接方法在SQL中获取此代码...我在VB6 ADODC中编写它,这是否与标准SQL中的语法相同?感谢
答案 0 :(得分:58)
如果要针对Access数据库后端编写查询,则需要使用以下连接语法:
select
t1.c1
, t2.c2
, t3.c3
, t4.c4
from ((t1
inner join t2 on t1.something = t2.something)
inner join t3 on t2.something = t3.something)
inner join t4 on t3.something = t4.something
这里的表名和列名并不重要,但括号的位置是。基本上,你需要在from
子句之后有 n - 2 左括号,并且在每个新join
子句开始之前有一个右括号,除了第一个,其中 n 是连接在一起的表的数量。
原因是Access的连接语法一次只支持连接两个表,因此如果需要连接两个以上,则需要将多余的表括在括号中。
答案 1 :(得分:2)
SELECT tblOjt.id, tblStudent.firstname, tblStudent.middlename,
tblStudent.lastname, tblStudent.course, tblCompany.companyname,
tblAddressee.addressee
FROM (((tblOjt
INNER JOIN tblStudent ON tblOjt.studentid = tblStudent.id)
INNER JOIN tblCourse ON tblOjt.courseid = tblCourse.id)
INNER JOIN tblCompany ON tblOjt.companyid = tblCompany.id)
INNER JOIN tblAddressee ON tblOjt.addresseeid = tbladdressee.id
发现它!感谢Yawar的做法......
答案 2 :(得分:0)
一直在尝试使用VBA运行此SQL,但不会使用DoCmd.RunQuery运行。我已经尝试了SQL,但它正在工作。
str = "SELECT tbl_company.[Company], tbl_company.[Commodity], tbl_company.[Segment], tbl_company.[MainProduct]," & _
" tbl_financials.[DataYear]," & _
" mstr_financial.[FinancialData]," & _
" tbl_financials.[Amount]," & _
" tbl_financials.[Unit]," & _
" tbl_company.[CompanyID]" & _
" FROM (tbl_company" & _
" INNER JOIN tbl_financials ON tbl_company.[CompanyID] = tbl_financials.[CompanyID])" & _
" INNER JOIN mstr_financial ON tbl_financials.[FinID] = mstr_financial.[FinID] " & _
" ORDER BY tbl_company.[Company], tbl_financials.[DataYear] DESC"