我无法理解如何INNER JOIN多个表
以下是我的表格
STUDENT
id | fname | surnamee | courseCode
-----------------------------------------------------------
11221 | Donal | Nee | GY101
12345 | Ann | Apple | GY350
33445 | Jack | Carr | GY101
44554 | Mark | Connor | GY350
55566 | Claire | Gavin | GY350
98981 | Marie | Fahy | GY101
99887 | Hugh | Flynn | GY350
STUDENT_REG1
sID | modCode
--------------------
11221 | CT2101
11221 | CT2103
11221 | CT230
11221 | EC273
11221 | EC275
12345 | CT229
12345 | CT230
12345 | CT231
12345 | CT237
33445 | CT335
44554 | CT230
98981 | CT2101
MODULES1
code | modName | deptName
-------------------------------------
CT2101 | OOP 1 | IT
CT2103 | SAD | IT
CT229 | Programming1 | IT
CT230 | Database | IT
CT231 | Pro Skills | IT
CT335 | OOP | IT
CT874 | Programming1 | IT
EC273 | Maths Eco | Maths
EC275 | Statistics | Maths
ST237 | Intro SDP | Maths
ROOM_BOOKING1
bookingID | roomCode | moduleCode | dayReq | timeReq
-----------------------------------------------------------------------------
1 | AM200 | CT230 | Tuesday | 14:00:00
10 | AM200 | ST237 | Tuesday | 16:00:00
11 | SC005 | EC273 | Monday | 17:00:00
12 | AM150 | EC273 | Tuesday | 15:00:00
13 | IT204 | CT335 | Monday | 11:00:00
14 | SC002 | CT335 | Wednesday | 16:00:00
2 | AM200 | CT230 | Wednesday | 12:00:00
3 | IT250 | CT229 | Friday | 13:00:00
4 | Ac005 | CT2103 | Monday | 14:00:00
5 | AM200 | CT237 | Monday | 16:00:00
6 | IT125G | CT2101 | Monday | 12:00:00
7 | IT204 | CT2101 | Tuesday | 12:00:00
8 | AC216 | CT2103 | Friday | 12:00:00
9 | UC102 | CT229 | Friday | 12:00:00
MOD_LECTURER1
mCode | lecturer
-----------------------
CT2101 | Seamus
CT2103 | Josephine
CT230 | Josephine
CT231 | Martina
CT231 | Pat
CT335 | Matthias
CT335 | Seamus
ST237 | John
ROOM1
rCode | rName | building | capacity | diabledAccess
----------------------------------------------------------------------------
AC216 | | Arts Con | 70 | -1
AM150 | Tnuthail | Arts Mil | 150 | -1
AM200 | Fottrell | Arts Mil | 200 | -1
ENG-2001 | | Engineering | 60 | -1
ENG-2002 | | Engineering | 60 | -1
IT125 | | IT | 125 | -1
IT125G | | IT | 125 | -1
IT204 | | IT | 59 | -1
IT250 | | IT | 250 | -1
SC002 | Larmor | Arts Con | 100 | 0
SC005 | Tyndall | Arts Con | 100 | 0
UC102 | | Aras Uí | 166 | 0
我需要使用INNER JOIN列出学生ID，姓名和总人数 学生每周的时间表，学生的时间超过 每周4小时
这是我到目前为止所拥有的
SELECT id, fname, surname, COUNT(*) AS "HOURS"
FROM STUDENT
INNER JOIN
STUDENT_REG1 ON STUDENT_REG1.sID = STUDENT.id
INNER JOIN
MODULES1 ON MODULES1.code = STUDENT.id
INNER JOIN
ROOM_BOOKING1 ON ROOM_BOOKING1.moduleCode = STUDENT.id;
GROUP BY roomCode
HAVING COUNT(*) >4;
它似乎无法工作但我不明白该怎么做，这是我得到的错误信息
Syntax errpr (missing operator) in query expression 'STUDENT_REG1.sID = STUDENT.id
INNER JOIN
MODULES1 ON MODULES1.code = STUDENT.id
INNER JOIN
ROOM_BOOKING1 ON ROOM_BOOKING1.moduleCode = STUDENT.i'.
有人可以告诉我如何正确地写它