我编写了一些代码,用于请求用户输入并将其分配给String skillAssign。当我试图评估skillAssign时,无论如何都会返回false。这是我的代码:
import java.util.*;
public class CharacterCustomization
{
public CharacterCustomization()
{
}
public static void Customization()
{
Scanner keyboard = new Scanner(System.in);
int skillPoints = 100;
String skillAssign = "";
int newMaxHealth = 0;
int newMaxMagic = 0;
int newMaxStamina = 0;
int assignmentValue = 0;
boolean isDone = false;
System.out.println("Welcome to character customization, you have 100 points to allocate to your skills.");
System.out.println("To allocate points, type name of skill, followed by the points you want to assign (blank for positive, - for negative, ex. -5)");
System.out.println("Put Skill on one line, and press enter, then the value on the next line");
System.out.println("Type \"stats\" to view full stats at any time");
System.out.println("Type \"done\" to finish");
while (true)
{
while (isDone == false)
{
skillAssign = keyboard.nextLine();
if (skillPoints == 0)
{
System.out.println("Max Health: " + newMaxHealth);
System.out.println("Max Magic: " + newMaxMagic);
System.out.println("Max Stamina: " + newMaxStamina);
System.out.println("Skill points left: " + skillPoints);
System.out.println("Type \"done\"to finish");
}
if ((!(skillAssign.equals("stats"))) || (!(skillAssign.equals("done"))))
{
assignmentValue = keyboard.nextInt();
if (((skillAssign.equals("health")) || (skillAssign.equals("Health"))) && (skillPoints - assignmentValue >=0))
{
skillPoints = (skillPoints - assignmentValue);
newMaxHealth = (assignmentValue + newMaxHealth);
}
else if (((skillAssign.equals("magic")) || (skillAssign.equals("Magic"))) && (skillPoints - assignmentValue >=0))
{
skillPoints = (skillPoints - assignmentValue);
newMaxMagic = (assignmentValue + newMaxMagic);
}
else if (((skillAssign.equals("stamina")) || (skillAssign.equals("Stamina"))) && (skillPoints - assignmentValue >=0))
{
skillPoints = (skillPoints - assignmentValue);
newMaxStamina = (assignmentValue + newMaxStamina);
}
else
{
//System.out.println("Sorry, I could not read that!");
System.out.println(skillAssign == "stats");
}
}
else if (skillAssign.equals("stats"))
{
System.out.println("Max Health: " + newMaxHealth);
System.out.println("Max Magic: " + newMaxMagic);
System.out.println("Max Stamina: " + newMaxStamina);
System.out.println("Skill points left: " + skillPoints);
}
else if ((skillAssign.equals("done")) || (skillAssign.equals("Done")))
{
isDone = true;
continue;
}
else
{
System.out.println("Sorry, I could not read that!");
}
}
System.out.println("Are you sure this is the setup you want? [y] [n]");
System.out.println("Max Health: " + newMaxHealth);
System.out.println("Max Magic: " + newMaxMagic);
System.out.println("Max Stamina: " + newMaxStamina);
System.out.println("Skill points left: " + skillPoints);
//skillAssign = keyboard.nextLine();
if (((keyboard.nextLine()).equals("y")) || ((keyboard.nextLine()).equals("Y")) || ((keyboard.nextLine()).equals("yes")) || ((keyboard.nextLine()).equals("Yes")))
{
Player player = new Player(newMaxHealth, newMaxMagic, newMaxStamina);
}
else
{
isDone = false;
}
}
}
}
它不完整,但我在提示时输入stats
并且对它的所有评估都是错误的
有没有办法让它正确读取变量?
答案 0 :(得分:1)
您将始终进入此条件范围if ((!(skillAssign.equals("stats"))) || (!(skillAssign.equals("done"))))
因为当一个单词未能通过它时,另一个条件会让它通过,因为它们完全不同。
例如:
让我们采取" stats",这将导致if(false || true)=>真的。
让我们来完成",这将产生if(true || false)=>真的。
让我们来看看" sTats",这会产生if(true || true)=>真。
你无法逃脱它,你需要检查它:
if (!(skillAssign.equals("stats") || skillAssign.equals("done")))
这样我们就可以检查逻辑表达式是否为真,然后我们将其更改为"而不是"然后检查整个条件是否成立。
<强> P.S 强>
答:您可以使用&#34; abc&#34; .equalsIgnoreCase(&#34; AbC&#34;)代替您现在使用的内容。
B.不要为每个逻辑表达式括号添加它使得代码更复杂,第一眼看不清楚。
答案 1 :(得分:0)
问题是我在||
&&
而不是if ((!(skillAssign.equals("stats"))) || (!(skillAssign.equals("done"))))
答案 2 :(得分:0)
Orel所说的几乎就是它。如果您正在使用System.out.println(skillAssign == "stats")
来评估您的skillAssign,它将总是返回false,即使它们具有相同的值。
因为==
比较字符串的引用而不是它们的值。
你必须使用equals()
方法。