Question

这是我到目前为止所做的：

echo "Please enter your first number: "
read a
echo "Second number: "
read b

（等）这很好，但是当我尝试为sum average和product设置函数时，我遇到了一些问题。

这就是我的尝试：

sum= ($a + $b + $c + $d + $e)
avg= ($sum / 5) #The five was showing up in red text
prod= ($a * $b * $c * $d * $e)

echo "The sum of these numbers is: " $sum
echo "The average of these numbers is: " $avg
echo "The product of these numbers is: " $prod

但是当我运行它（在我输入数字1,2,3,4,5之后）后，我得到了回复：

The sum of these numbers is: 1 + 2 + 3 + 4 + 5
The average of these numbers is:  1 + 2 + 3 + 4 + 5 / 5
The product of these numbers is: 1 * 2 * 3 * 4 * 5

所以我的问题是我如何在（）

中计算这些函数

感谢任何帮助，谢谢。

Answer 1

read N
i=1
sum=0
while [ $i -le $N ]
do
  read num          
  sum=$((sum + num))     
  i=$((i + 1))
done
avg1=$(echo $sum / $N | bc -l);
echo "scale = 3; $avg1 / 1" | bc -l

此代码对我有用。感谢-oogy。对于这一部分

echo“ scale = 3; $ avg1 / 1” | bc -l`

Answer 2

试试这个：

#!/bin/bash

echo "Please enter your first number: "
read a
echo "Second number: "
read b
echo "Third number: "
read c
echo "Fourth number: "
read d
echo "Fifth number: "
read e

sum=$(($a + $b + $c + $d + $e))
avg=$(echo $sum / 5 | bc -l ) 
prod=$(($a * $b * $c * $d * $e))

echo "The sum of these numbers is: " $sum
echo "The average of these numbers is: " $avg
echo "The product of these numbers is: " $prod

唯一的问题是sum，avg，prod部分的一些小的语法问题。

平均值不像其他计算那样完成，因为它可能返回浮点数。此号码通过管道传输至bc并存储在avg。

当我运行这个程序时，我得到了结果：

Please enter your first number: 
2
Second number: 
2
Third number: 
2
Fourth number: 
3
Fifth number: 
2
The sum of these numbers is:  11
The average of these numbers is:  2.20000000000000000000
The product of these numbers is:  48

Shell脚本，查找总和平均值和五个数字的乘积

2 个答案: