Question

下午好，我被要求做一个叫做void printStatistics（int n）的函数，该函数应该打印传入的n个数的平均值，和，最小和最大数。例如，如果我执行了printStatistics（5），那么我应该要求用户输入5次数字，然后打印统计信息。我所要做的就是创建一个while循环，要求用户输入数字，直到输入负数为止，但是将其转换为要求用户输入数字n次然后打印出来的函数似乎有些麻烦。总和，平均值，最小值和最大值。这就是我所拥有的。

int main()
{
    int value, sum;
    int average, min, max;
    int count;

    sum = 0;
    count = 0;

    cout << "Enter a number: " << endl;
    cin >> value;

    min = value;
    max = value;

    while(value >= 0)
    {
        sum += value;
        count++;
        if(value > max)
            max = value;
        else if(value < min)
            min = value;

        cout << "Enter a numnber: " << endl;
        cin >> value;
    }
    if(count == 0)
        cout << "Nothing entered." << endl;
    else
    {
        average = sum / count;
        cout << "Average is " << average << endl;
        cout << "Minimum is " << min << endl;
        cout << "Maximum is " << max << endl;
        cout << "Sum is " << sum << endl;
    }
}

Answer 1

根据我对问题的理解，您希望有一个函数（printStatistics），该函数的参数'int n'和'n'与用户希望输入的数字量相对应。然后，您要求提供这些特定的数字，然后找到该集合的MIN，MAX，SUM和AVERAGE。如果我正确理解了这一点，那么应该可以解决这个问题：

#include <iostream>

void printStatistics(int n);


void printStatistics(int n)
{
    int response;
    int sum = 0;
    int max;
    int min;

    for (int i = 1; i <= n; ++i)
    {
        std::cout << "Please enter the number in the " << i << " position: ";
        std::cin >> response;
        if (i == 1)
        {
            min = response;
            max = response;
        }
        (min > response) ? min = response : min = min;
        (max < response) ? max = response : max = max;
        sum += response;
    }
    std::cout << "Sum: " << sum << std::endl;
    std::cout << "Average: " << (float)sum / n << std::endl;
    std::cout << "Min: " << min << std::endl;
    std::cout << "Max: " << max << std::endl;
}


int main()
{
    int numberCount;
    do
    {
        std::cout << "How many numbers would you like to print? ";
        std::cin >> numberCount;
    }while(numberCount <= 0);
    printStatistics(numberCount);   
}

c函数查找传入的n个数的平均值，和，最小值和最大值

1 个答案: