Question

当我在代码下面运行时，我的预期输出是玩家应该连续动画，当用户点击屏幕时，玩家应该跳跃。我的播放器的帧不同，跳帧也不同。我在鼠标左键单击时调用帧。处理所有帧但速度过快，因此动画不可见。

    private void OnUpdate(object sender, GameTimerEventArgs e)
    {
        float elapsed = (float)e.ElapsedTime.TotalSeconds;
        timer5 -= elapsed;

        TouchPanel.EnabledGestures = GestureType.Tap;
        TouchCollection touches = TouchPanel.GetState();

        MouseState mousestate = Mouse.GetState();

        //Texture.position += velocity;
        //if (rect.Contains(new Microsoft.Xna.Framework.Point(mousestate.X, mousestate.Y)) && mousestate.LeftButton == ButtonState.Pressed)

        if (mousestate.LeftButton==ButtonState.Pressed)
        {
            for (int i = 0; i < 32; i++)
            {

               jump();
                jumpframe++;
                if (jumpframe > 24)
                {
                    jumpframe = 0;
                }
                System.Diagnostics.Debug.WriteLine("currentframe:"+ jumpframe);
            }
        }

        if (timer5 <= 0)
        {
            playerr();
            currentframe++;
            if (currentframe > 24)
            {
                currentframe = 0;
            }
            timer5 = TIME_BET_FRAME;
        }
    }

    private void OnDraw(object sender, GameTimerEventArgs e)
    {
        SharedGraphicsDeviceManager.Current.GraphicsDevice.Clear(Color.CornflowerBlue);
        spriteBatch.Begin();

        //level.Draw(spriteBatch);
        rect2 = new Rectangle(0, 0, 960, 620);
        rect = new Rectangle(0, 0, 420, 300);

        spriteBatch.Draw(Texture.player[currentframe], Texture.position, Color.White);
        spriteBatch.Draw(Texture.jumpplayer[jumpframe], Texture.jumpposition,                 Color.White);
        spriteBatch.Draw(Texture.jumpbtn, Texture.rect, Color.White);
        spriteBatch.DrawString(font, "Score", new Vector2(10, 0), Color.Gold);
        spriteBatch.End();
    }

    public void jump()
    {
        Texture.jumpposition.X = 10;
        Texture.jumpposition.Y = 243;
        Texture.position.X = -400;
        Texture.position.Y = 243;    
    }

    public void playerr()
    {
        Texture.position.X = 10;
        Texture.position.Y = 243;
        Texture.jumpposition.X = -400;
        Texture.jumpposition.Y = 243;
    }

Answer 1

我看到的是循环

for(int i=0;i<32;i++){...}

在OnUpdate。

中一次绘制完整的跳转动画

你能做什么呢？

bool _jump;

private void OnUpdate(object sender, GameTimerEventArgs e)
{
    // ...
    if (mousestate.LeftButton==ButtonState.Pressed)
    {
         if(!_jump)
         {
             // start jumping
             _jump = true;
         }
         else
         {
             // jumping in progress
             _jumpframe++;
             // end of jumping check
             if(_jumpframe > 24)
             {
                 _jumpframe = 0;
                 _jump = false;
             }
         }
         jump();
    }
}

这应该以{{1}}的速度（频率）执行跳跃动画。

单击鼠标按钮后动画不正确

1 个答案: