Question

我正在为学校的作业制作这个课程，但是我们需要获得获得Yahtzee所需的最多卷数以及获得Yahtzee所需的最少卷数。然后我们需要找到平均卷数。目前，我对确定最高和最低数量的卷以获得Yahtzee的问题感到困惑。任何人都可以帮助我，我会非常感激。该程序运行直到获得100个天然Yahtzees。

#include <stdio.h> 
#include <stdlib.h>
#include <time.h> 
#include <limits.h>

int main( void )
{  // MARKS THE BEGINNING OF THE main( ) BLOCK OF STATEMENTS

int die1 = 0 , die2 = 0 , die3 = 0 , die4 = 0, die5 = 0 , roll = 0 ;
int lownr = INT_MAX , highnr = 0 , yahtzee = 0 , averagenr;
int roll_total = 0 ;
srandom ( (unsigned) time (NULL) ) ; 

printf( "\nWelcome User, this program demonstrates the " ) ;
printf( "number of rolls it takes to obtain" ) ; 
printf( "\na natural Yahtzee.\n" ) ;

die1 = random ( ) % 6 + 1;
die2 = random ( ) % 6 + 1;
die3 = random ( ) % 6 + 1;
die4 = random ( ) % 6 + 1;
die5 = random ( ) % 6 + 1;

printf( "\nYou rolled: %d, %d, %d, %d, %d.\n\n" , die1 ,
         die2 , die3 , die4 , die5 ) ;

while (yahtzee < 100) {

++roll;
++roll_total;

die1 = random ( ) % 6 + 1;
die2 = random ( ) % 6 + 1;
die3 = random ( ) % 6 + 1;
die4 = random ( ) % 6 + 1;
die5 = random ( ) % 6 + 1;


if ((die1==die2) && (die2==die3) && (die3==die4) && (die4==die5)) {

yahtzee = yahtzee +1;

    /* If you have yahtzee, compare roll with previous values of highnr/lownr */
    if (roll>highnr)
        highnr = roll;
    if (roll<lownr)
        lownr = roll;

    /* Reset the roll counter, for next yahtzee */
    roll = 0;
    }

    }
    averagenr = roll_total / yahtzee ;


    printf("\n The total number of yahtzees you rolled is: %d.",yahtzee);
    printf("\n The total number of times you rolled is: %d.",roll_total);
    printf("\n The highest number of rolls to get a yahtzee is: %d",highnr);
    printf("\n The lowest number of rolls to get a yahtzee is: %d", lownr);
    printf("\n The average number of rolls to obtain a yahtzee is: %d", 
       averagenr);
    printf ( "\n\n Thank you for using this program. " ) ;
    printf ( "GoodBye.\n\n " ) ;

    return ( 0 ) ;

    }

示例输出

Welcome User, this program demonstrates the number of rolls it takes to obtain
a natural Yahtzee.

You rolled: 5, 5, 3, 2, 1.


The total number of yahtzees you rolled is: 100.
The total number of times you rolled is: 116704.
The highest number of rolls to get a yahtzee is: 5284
The lowest number of rolls to get a yahtzee is: 18
The average number of rolls to obtain a yahtzee is: 1167

Thank you for using this program. GoodBye.

解决

Answer 1

据我所知，关键是你需要使用两个计数器来计算卷数。一个用于总卷数，您将在稍后用它来计算平均值，另一个用于跟踪当前滚动数量到下一个yahtzee。

int roll=0, roll_total=0;
int lownr=INT_MAX, highnr=0, averagenr;

while(yahtzee < 100) {

    ++roll; /* This will keep track of the number of rolls towards next yahtzee */
    ++roll_total; /* This is total number of rolls in entire program */

    if ((die1==die2) && (die2==die3) && (die3==die4) && (die4==die5)) {

        yahtzee = yahtzee +1;

        /* If you have yahtzee, compare roll with previous values of highnr/lownr */
        if (roll>highnr)
            highnr = roll;
        if (roll<lownr)
            lownr = roll;

        /* Reset the roll counter, for next yahtzee */
        roll = 0;
    }
}

averagenr = roll_total / yahtzee ;

修改

我用其他评论回答了您的评论，但评论中的代码变得难以理解，所以我会帮助您更多。仔细查看更新的代码并从代码中删除这些行：

lownr = roll; highnr = roll;

获取有关在C中滚动自然yahtzee的统计数据的麻烦

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