我正在尝试从ArrayList中删除一个对象。每个Item对象都有3个属性; 1. itemNum 2. info 3.成本。我还有3个类,1。Item类定义存储在目录中的单个项。 2. Catalog类维护Item对象的列表。 3客户端类w / main方法。 我有集合并获取Item类,我在Catalog中有ArrayList。在客户端中,我提示“输入要删除的itemNum。如何根据搜索itemNum从ArrayList中正确删除Item对象?下面是我的代码以及到目前为止我尝试过的内容。
Public class Item
{
private int itemNum;
private String info;
private double cost;
private int itemNum;
public Item()
{ //start constructor
itemNum = 0; //default values
info = "x";
cost = 0;
} //end constructor
public CatalogItem(int newItemNum, String newInfo, double newCost)
{ //start overload constructor
this.itemNum = newItemNum;
this.info = newInfo;
this.cost = newCost;
} //end overload constructor
//下面是itemNum的set / gets。我也有成本和信息的设置/获取,但选择不包括做空间
public int getItemNum()
{ //start itemNum accessor
return itemNum;
} //end getItemNum
public void setItemNum(int newItemNum)
{ //start itemNum mutator
this.itemNum = newItemNum;
} //end setItemNum
} //end Item class
public boolean equals(CatalogItem obj)
{ //start equals
if (itemId == obj.itemId)
return true;
else
return false;
} //end equals
//下面是我的目录类
import java.util.*;
public class Catalog
{ //start class
private ArrayList<CatalogItem> listOfObjects = new ArrayList<CatalogItem>(100); //creates ArrayList
Item newItem = new Item(newItemNum, newInfo, newCost);
public void remove(int id)
{ //start remove
int item = id;
for (int index = 0; index < listOfObjects.size(); index++)
if (newItem.getItemId() == item) //if item in the inventory matches the item number passed
listOfObjects.remove(index); //removes based on index, I’ve also tried listOfObjects.remove(item);
/* I’ve also tried an enhanced for loop
for (CatalogItem obj : listOfObjects)
if (newItem.getItemId() == item)
listOfObjects.remove(newItem); */
} //end remove
}
//下面是主要的。它接收用户关于itemNum,info和cost
的输入 import java.util.*; //allows use of Scanner class
public class Client
{ //start client class
public static void main(String[] args)
{ //start main
Catalog serv = new Catalog(); //creates instance of Catalog class
Scanner scan = new Scanner(System.in); //creates instance of Scanner class called scan
System.out.print("\nEnter in the Item ID you want to remove: ");
id = scan.nextInt();
serv.remove(id); //sends id to Catalog Class to be removed
} //end main
} //end class
它编译得很好,但不会根据找到的索引删除。任何帮助都会很棒。
答案 0 :(得分:7)
覆盖equals
课程中的Item
方法。您可以使用itemNum
检查equals方法中对象的相等性。
然后使用ArrayList remove(Object o)
方法删除对象。 remove
方法在内部使用equals
来查找要删除的对象。
修改强>
你没有正确地覆盖equals方法,这是正确的签名和实现:
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Item other = (Item) obj;
if (itemNum != other.itemNum)
return false;
return true;
}
答案 1 :(得分:2)
确保在对象类中覆盖等于。
答案 2 :(得分:0)
要从列表中删除对象,您需要先找到对象。您可以实现Comparable
接口并覆盖compareTo()
方法以找出对象。
Public class CatalogItem implements Comparable
{
private int itemNum;
private String info;
private double cost;
private int itemNum;
public Item()
{ //start constructor
itemNum = 0; //default values
info = "x";
cost = 0;
} //end constructor
public CatalogItem(int newItemNum, String newInfo, double newCost)
{ //start overload constructor
this.itemNum = newItemNum;
this.info = newInfo;
this.cost = newCost;
} //end overload constructor
public int compareTo(catalogItem c){
if(c.getItemNum == this.getItemNum()){
return 0;// zero means both are equal
}
}
}
当您获得itemNum
表单输入时,创建一个CatalogItem
对象并设置此值并迭代列表以检查相等性。如果您找到它,然后从列表中删除,但请确保您没有从同一列表中删除,否则您可以获得Concurrency Exception
。