Question

我没有得到我的语法错误，MySql说未知的系统可以完成：分隔符|

CREATE PROCEDURE UPDATELOMON ()    
BEGIN 

  DECLARE First_cur CURSOR FOR SELECT oraginal_level,level FROM LOMTEMP;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done := TRUE;

  OPEN First_cur;

  FirstLoop: LOOP
  FETCH First_cur INTO oraginal,toupdate;
  IF done THEN
  LEAVE FirstLoop;
  END IF;

  CALL updt(oraginal,toupdate);
  END LOOP FirstLoop;

  CLOSE First_cur;

END;

Answer 1

创建STORED PROCEDURE时需要更改分隔符：

DELIMITER $$

DROP PROCEDURE IF EXISTS UPDATELOMON$$
CREATE PROCEDURE UPDATELOMON ()    
BEGIN 

  DECLARE First_cur CURSOR FOR SELECT oraginal_level,level FROM LOMTEMP;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done := TRUE;

  OPEN First_cur;

  FirstLoop: LOOP
  FETCH First_cur INTO oraginal,toupdate;
  IF done THEN
  LEAVE FirstLoop;
  END IF;

  CALL updt(oraginal,toupdate);
  END LOOP FirstLoop;

  CLOSE First_cur;

END$$
DELIMITER ;

默认情况下，MySQL本身将分号识别为语句分隔符，因此必须临时重新定义分隔符以使MySQL将整个存储的程序定义传递给服务器。否则，MySQL会在它到达END语句之前打破CREATE PROCEDURE（在第一个分号上，在你的情况下，在CONTINUE HANDLER语句之前）。

您可以查看文档了解更多详情： http://dev.mysql.com/doc/refman/5.5/en/stored-programs-defining.html

Answer 2

关于@ Zagor23的回答。您可以在$$行删除DROP PROCEDURE...，然后在DELIMITER $$后面添加DROP PROCEDURE IF EXISTS UPDATELOMON; DELIMITER $$。所以你将拥有以下内容：

//
//  ViewController.swift
//  MyCalculator
//
//  Created by Kevin Maldjian on 2/6/17.
//  Copyright © 2017 Kevin Maldjian. All rights reserved.
//

import UIKit
import Foundation

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    @IBOutlet weak var LBLOutput: UILabel!
    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()

    }





    @IBAction func btrNumberClick(_ sender: UIButton) {
        let cb = calculatorBrain(LBLOutput: LBLOutput , sender: sender)
        cb.btrNumberClick()

    }


    @IBAction func clearTheLabel(_ sender: Any) {
        let cb = calculatorBrain(LBLOutput: LBLOutput, sender: sender as! UIButton)
        cb.clearTheLabel()
    }

    @IBAction func goNegative(_ sender: Any){
        let cb = calculatorBrain(LBLOutput: LBLOutput, sender: sender as! UIButton)
        cb.goNegative()
}

    @IBAction func squareRoot(_ sender: Any) {
        let cb = calculatorBrain(LBLOutput: LBLOutput, sender: sender as! UIButton)

        cb.squareRoot()
}
}

存储过程继续处理程序错误

2 个答案: