Question

我有一张二进制图片。我想找到像素值= 1并将其标记为当前像素。然后，我想将其8个邻居像素值相加。如果当前像素的8个相邻像素值的总和= 1，则用标记标记该当前像素。二进制图像的某些部分如下：

0 0 0 0 0
0 1 0 0 0
0 0 1 1 0
0 0 0 0 1
0 0 0 0 0

我尝试了以下matlab代码，但它有一些错误（在此行 - ＆gt; Sums = sum(currentPix, nOffsets);)。我该如何解决？

Sums = 0; 
S = size(BW,1);
nOffsets = [S, S+1, 1, -S+1, -S, -S-1, -1, S-1]';  %8-neighbors offsets
BW_Out = BW;

for row=1:S    
   for col=1:S 
     if BW(row,col),
         break; 
      end 
   end 

   idx = sub2ind(size(BW),row,col);
   neighbors = bsxfun(@plus, idx, nOffsets); 
   currentPix = find(BW==1); %if found 1, define it as current pixel 

     while ~isempty(currentPix)

        % new current pixel list is  set of neighbors of current list.
        currentPix = bsxfun(@plus, currentPix, nOffsets);
        currentPix = currentPix(:);
        Sums = sum(currentPix, nOffsets); %error at this line

        if (Sums==1)   %if the sum of 8-neighbor values = 1, mark ROI
            plot(currentPix,'r*','LineWidth',1);
        end

        % Remove from the current pixel list pixels that are already
        currentPix(BW_Out(currentPix)) = [];

        % Remove duplicates from the list.
        currentPix = unique(currentPix);
    end
end

Answer 1

我认为你可以在一行中实现这一点（在定义内核之后）

I = [0 0 0 0 0
     0 1 0 0 0
     0 0 1 1 0
     0 0 0 0 1
     0 0 0 0 0];

K = [1 1 1;
     1 0 1;
     1 1 1;];

(conv2(I,K,'same')==1) & I

ans =

   0   0   0   0   0
   0   1   0   0   0
   0   0   0   0   0
   0   0   0   0   1
   0   0   0   0   0

打破这个局面：

M = conv2(I,K, 'same'); %// convolving with this specific kernel sums up the 8 neighbours excluding the central element (i.e. the 0 in the middle)

(M==1) & I %// Only take results where there was a 1 in the original image.

如何对当前像素的8个邻居像素值求和。

1 个答案: