Question

如果我们的客户服务联络中心关闭，我们需要能够在我们的网站上显示消息。我正在尝试清理代码，检查当天是否是假日。

过去我每个假期使用一个变量，每个假期使用一个if语句。这是很多代码，它看起来很草率和不专业。我一直在阅读多维数组，看起来这可能是一个可行的解决方案。

以下是我的数组示例：

//Store Holidays in multidimensional array
$holidays = array
(
  "NewYearsDay"=>array
    (
      "Date"=>"01-01-2014",
      "Closed"=>"Yes"
    ),
  "MartinLutherKingJrDay"=>array
    (
      "Date"=>"01-21-2013,
      "Closed"=>"Yes"
    )
);

这给了我以下（这很好 - 这部分没问题）

Array
(
    [NewYearsDay] => Array
        (
            [Date] => 01-01-2014
            [Closed] => Yes
        )

    [MartinLutherKingJrDay] => Array
        (
            [Date] => 01-21-2013
            [Closed] => Yes
        )

)

但是，当我使用foreach循环时，我只能获得假期的名称。我想得到日期和结束信息。

foreach ($holidays as $key => $value) {
    echo $key;

只给我： NewYearsDayMartinLutherKingJrDay（我稍后可以处理的间距问题）

我希望最终能够做到这样的事情：

//loop through the array and do this for each iteration:
if ((NewYearsDay['date'] == date('d-m-Y')) && (NewYearsDay['closed'] == Yes)) {
    $status = "closed";
}

Answer 1

忽略$key并使用$value来覆盖您的数据。

foreach ($holidays as $value) {
    var_dump($value);
    if (($value['date'] == date('d-m-Y')) && ($value['closed'] == 'Yes')) {
        $status = "closed";
    }
}

Answer 2

正如diegoperini上面提到的，这里有一个稍微有点文档的版本：

foreach ($holidays as $name => $value) {
    // $name should be there, it contains your "MartinLutherKingDay" etc, 
    // could be handy.
    // although I'd put the formatted display name into your array:
    // $value['name'] = 'Martin Luther King Day';
    list($date, $closed) = $value;

    if ($date == date('d-m-Y')) && ($closed == 'Yes')) {
        // if you find what you want, and you only want one, you can skip
        // the rest of the foreach
        $status = "closed";
        continue;
    }
}

如何使用foreach与多维数组？

2 个答案: