我想测试一个矩阵的列名是否包含在矩阵的rownames中,即如果colnames(abun)和包含在rownames(x)中的示例如下
abun <- matrix(c(0.4,0,0.6,0.1,0.4,0.5),
nrow = 2, ncol = 3, byrow = TRUE, dimnames = list(c("x", "y"),
c("A","B","C")))
abun
A B C
x 0.4 0.0 0.6
y 0.1 0.4 0.5
x<-data.frame("Trait1" =c(1,1,0,1),
"Trait2"=c(1,1,1,1),
"Trait3" =c(1,1,0,1),
"Trait4" =c(1,0,1,1))
rownames(x)<-c("A","B","C","D")
x
Trait1 Trait2 Trait3 Trait4
A 1 1 1 1
B 1 1 1 0
C 0 1 0 1
D 1 1 1 1
更新: 我正在编写一个函数,如果rownames(x)中没有包含colnames(abun),则会抛出一条错误消息。我试过了:
if(colnames(abun) %in% rownames(x) = FALSE)
stop("species names in abun and x do not match")
答案 0 :(得分:1)
colnames(abun)[
colnames(abun) %in% rownames(x)
]
colnames(abun) %in% rownames(x)
返回一个true / false向量,指示colnames(abun)
中rownames(x)
上的哪个元素。
答案 1 :(得分:1)
你只是要求两套交叉吗?
intersect(c("A","B","C","D") ,
c("A","B","C"))
[1] "A" "B" "C"
要获得差异,请使用setdiff
:
setdiff(c("A","B","C","D") ,
c("A","B","C"))
[1] "D"