我目前正试图在我的窗口中绘制像素,而且我似乎遇到了程序启动时索引越界错误。老实说,我不知道如何解决它。谁能告诉我问题出在哪里?我已经检查了很多次,但似乎对我来说应该没问题。我已经为下面的项目提供了所有代码,但错误是在for循环所在的render方法(Game类)中的行。
编辑:
错误发生在Game类的for循环中。它说
java.lang.ArrayIndexOutOfBoundsException:48601"在线 " pixles [i] = screen.pixels [i]"
屏幕类
public class Screen {
private int width,height;
public int[] pixels;
public Screen(int width,int height){
this.width = width;
this.height = height;
pixels = new int[width * height];
}
public void render(){
for (int y = 0; y < height; y++){
for (int x = 0; x < width; x++){
pixels[x + y * width] = 0xff00ff;
}
}
}
}
Game Class
import java.awt.Canvas;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.image.BufferStrategy;
import java.awt.image.BufferedImage;
import java.awt.image.DataBufferInt;
import javax.swing.JFrame;
public class Game extends Canvas implements Runnable{
private int width = 300;
private int height = width / 16 * 9;
private int scale = 3;
private Thread thread;
private boolean running = false;
private JFrame frame;
private BufferedImage image = new BufferedImage(width * scale, height * scale,BufferedImage.TYPE_INT_RGB);
private int[] pixels = ((DataBufferInt)image.getRaster().getDataBuffer()).getData();
private Screen screen;
public Game(){
screen = new Screen(width,height);
frame = new JFrame("Relm Of The Mad God Clone");
this.setPreferredSize(new Dimension(width * scale, height * scale));
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setResizable(false);
frame.add(this);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
start();
}
public synchronized void start(){
thread = new Thread(this,"Running Thread");
thread.start();
running = true;
}
public synchronized void stop(){
try{
thread.join();
running = false;
}catch (InterruptedException e){
e.printStackTrace();
}
}
public static void main(String[] args) {
Game g = new Game();
}
private void update(){
}
private void render(){
BufferStrategy buffer = getBufferStrategy();
if (buffer == null){
createBufferStrategy(3);
return;
}
screen.render();
for (int i = 0; i < pixels.length; i++){
pixels[i] = screen.pixels[i];
}
Graphics g = buffer.getDrawGraphics();
g.drawImage(image, 0, 0, getWidth(), getHeight(),this);
g.dispose();
buffer.show();
}
@Override
public void run() {
while (running){
update();
render();
}
}
}
答案 0 :(得分:1)
screen
变量已使用new Screen(width, height)
初始化,因此可能有width*height
像素。另一方面,pixels
变量是从image
初始化的,其width*scale * height*scale
像素。
从scale=3
开始,这意味着pixels
数组的长度是screen
数组的3倍。这就是你获得例外的原因。