Question

我试图让一个C程序使用来自clock_t的“秒”作为for循环计数器。这怎么可能？以下是我的编码无效，

#include<stdio.h>
#include <time.h>

int main()
{
  clock_t begin, end;
double time_spent;

begin = clock();
time_spent = (double)begin / CLOCKS_PER_SEC;

for(time_spent=0.0; time_spent<62000.0; time_spent++)
{
    printf("hello \n");

    if(time_spent==5.0)
    break;
}

end = clock();
time_spent = (double)(end - begin) / CLOCKS_PER_SEC;

    printf(" %lf\n", time_spent);
}

Answer 1

很难确切地说出你想要做什么（根据对你的问题的评论），但我猜它是这样的（循环将在5秒后终止）。请注意，clock（）在某种程度上取决于系统。有时它是挂钟时间，但它应该是CPU时间。

#include <stdio.h>
#include <time.h>

int main()
    {
    clock_t begin;
    double time_spent;
    unsigned int i;

    /* Mark beginning time */
    begin = clock();
    for (i=0;1;i++)
        {
        printf("hello\n");
        /* Get CPU time since loop started */
        time_spent = (double)(clock() - begin) / CLOCKS_PER_SEC;
        if (time_spent>=5.0)
            break;
        }
    /* i could conceivably overflow */
    printf("Number of iterations completed in 5 CPU(?) seconds = %d.\n",i);
    return(0);
    }

如何在C程序中使用秒（时间）作为计数器？

1 个答案: