我有一张桌子,我想要colum joint_no列。列的值类似于
FW-1
FW-2
.
.
.
FW-13
FW-R1
FW-1A
当我订购它时,我得到了这个结果
FW-1
FW-10
FW-11
FW-12
FW-13
FW-1A
.
.
FW-R1
我想在sql查询
之后得到这个结果FW-1
FW-1A
FW-2
FW-3
..
FW-13
FW-R1
任何人都可以帮助我吗?
答案 0 :(得分:2)
如果你能做到这一点,我建议你重新编号,使'逻辑'顺序符合字母顺序。然后F-1将更新为F-01或F-001。
如果您不能这样做,请添加一个将填充代码的“有序”形式的字段。然后,您将能够通过F-001列进行订购,并仍然显示F-1值
否则订购您的记录将很快成为您的噩梦。
答案 1 :(得分:0)
使用Patindex查找第一个数字表达式作为第一个排序字段,然后将数字部分提取为整数作为第二个排序字段,并使用整个字符串作为第三个排序字段,您可能会得到所需的结果。
Declare @a Table (c varchar(50))
Insert Into @a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
@a
) x
order by
s1,s2,c
输出:
FW-1 4 1 -1
FW-1A 4 1 -1A
FW-2 4 2 -2
FW-3 4 3 -3
FW-10 4 10 -10
FW-11 4 11 -11
FW-12 4 12 -12
FW-13 4 13 -13
FW-A1 5 1 A1
FW-R1 5 1 R1
如果未固定前导部分(FW-),则可能需要添加一个额外的排序字段
Declare @a Table (c varchar(50))
Insert Into @a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
Union Select 'AB-A1'
Union Select 'AB-11'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,SubString(c,1,PATINDEX('%[0-9]%',c)-1) as S0
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
@a
) x
order by
s0,s1,s2,c