Question

我的目标是输入三个数字并让程序吐出中间数字。这适用于System.out.println，但是当我必须使用JOptionPane时，它开始变得混乱。

这是我得到的代码：

public class ReturnMiddle {

public static void main(String[] args) {
    int num1 = 0;
    int num2 = 0;
    int num3 = 0;
    int smallest = returnMiddle(num1, num2, num3);

    String inputValue = JOptionPane.showInputDialog("What is your first number?");
    num1 = (Integer.parseInt(inputValue));

    inputValue = JOptionPane.showInputDialog("What is your second number?");
    num2 = (Integer.parseInt(inputValue));

    inputValue = JOptionPane.showInputDialog("What is your third number?");
    num3 = (Integer.parseInt(inputValue));

    JOptionPane.showMessageDialog(null, smallest);

}

    public static int returnMiddle(int num1, int num2, int num3) {

        //Returns the smaller of num1 and num2.
        int middle12 = Math.min(num1, num2);

        //Returns the smaller of num2 and num3.
        int middle23 = Math.min(num2, num3);

        //Returns the smaller of num1 and num3.
        int middle13 = Math.min(num1, num3);

        //Returns the larger of middle12 and middle13.
        int middleNumber1 = Math.max(middle12, middle13);

        //Returns the larger of middleNumber1 and middle23, which
        //ends up being the middle of the original 3 numbers.
        int middleNumber2 = Math.max(middleNumber1, middle23);

        //Makes the method "returnMiddle" return middleNumber2.
        return middleNumber2;

    }

}

当我输出三个数字时，我每次都得0。这是在两种不同方法中使用num1，num2和num3的问题吗？我是否将returnMiddle方法称为错误？

Answer 1

您必须在正确的位置使用该方法。目前，您计算结果FIRST并获得输入SECOND。你必须反过来这样做。

// dont calculate it here

String inputValue = JOptionPane.showInputDialog("What is your first number?");
num1 = (Integer.parseInt(inputValue));

inputValue = JOptionPane.showInputDialog("What is your second number?");
num2 = (Integer.parseInt(inputValue));

inputValue = JOptionPane.showInputDialog("What is your third number?");
num3 = (Integer.parseInt(inputValue));

// you have to calculate the middle one here.
int middle = returnMiddle(num1, num2, num3);

JOptionPane.showMessageDialog(null, middle);

Answer 2

您正在调用returnMiddle错误。在您阅读并分配输入后应该调用它。

public static void main(String[] args) {
int num1 = 0;
int num2 = 0;
int num3 = 0;
int smallest = Integer.MAX_VALUE;

String inputValue = JOptionPane.showInputDialog("What is your first number?");
num1 = (Integer.parseInt(inputValue));

inputValue = JOptionPane.showInputDialog("What is your second number?");
num2 = (Integer.parseInt(inputValue));

inputValue = JOptionPane.showInputDialog("What is your third number?");
num3 = (Integer.parseInt(inputValue));

smallest = returnMiddle(num1, num2, num3);

JOptionPane.showMessageDialog(null, smallest);

}

Answer 3

查看您的代码

int smallest = returnMiddle（num1，num2，num3）;

这里你实际上告诉编译器你希望var'minimum'等于returnMiddle函数的结果。由于用户输入是在调用该方法之后，您没有在该调用上将这些值传递给该函数，而实际上是初始化的0：

int smallest = returnMiddle（0,0,0）;

获得用户输入后，您需要调用该方法。

输入输入时输入0

3 个答案: