Question

创建一个更改计数游戏，让用户输入正好一美元所需的硬币数量。主要这包含程序的主线逻辑。它执行以下操作：要求用户输入以下数字： o便士 o镍 o角钱 o quarters将用户输入值转换为int值。调用computeValue函数并将这4个变量作为参数发送。

计算并显示总美元金额为便士。当总硬币等于1美元时，打印出一条消息。如果计算值小于$ 1，则显示金额，并显示消息，指示该值小于1美元，并打印出金额如果计算机价值大于1美元，则分别显示美元金额和美分。有关示例，请参阅示例输出。

我的样本包括5,3,3,2，我想要“我有1美元和25美分”而不是我得到5美元和5美分。

def main():
    pennies=int(input("Enter the Number of pennies : "))
    nickels = int(input("Enter the Number of nickels : "))
    dimes = int(input("Enter the Number of dimes : "))
    quarters =int(input("Enter the Number of quarters : "))

    pennies1=pennies*1
    nickels1=nickels*5
    dimes1=dimes*10
    quarters1=quarters*25

    total=pennies1 +nickels1+dimes1+quarters1
    cash=total//100
    change=total-cash*100
    computeValue(pennies1,nickels1,dimes1,quarters1)

def computeValue(pennies1,nickels1,dimes1,quarters1):
    print("You entered")
    if (pennies1 == 1):
        print ("You have exactely 1 dollar")
    elif (pennies1 < 1):
        print ("You have",pennies1,"which is less than 1 dollar")
    elif (pennies1 > 1):
        print ("pennies:",pennies1,"\nnickels:",nickels1,"\ndimes:",dimes1,
        "\nquarters:",quarters1,"\nYou have",pennies1,"dollars and",pennies1,"cents")

main()

Answer 1

您的程序对如何计算值非常困惑。
5*1 + 2*5 + 2*10 + 2*25 = 100，而不是125
你写pennies1, "dollars and", pennies1, "cents"这没有任何意义。

这应该按预期工作：

#!/usr/bin/env python


if __name__ == "__main__":
    pennies = int(input("Enter the Number of pennies : "))
    nickels = int(input("Enter the Number of nickels : "))
    dimes = int(input("Enter the Number of dimes : "))
    quarters = int(input("Enter the Number of quarters : "))

    cents = pennies
    cents += nickels*5
    cents += dimes*10
    cents += quarters*25

    dollars = int(cents / 100) 
    cents = cents % 100 

    print ("You entered {} pennies {} nickels {} dimes and {} quarters".format(pennies, nickels, dimes, quarters))
    print ("You have {} dollars and {} cents".format(dollars,cents))

    if dollars == 1 and cents == 0:
      print("You Win")
    else:
      print("you fail")

[edit]：如果您愿意，可以添加一些功能来解决问题：

def change_to_cents(pennies, nickels, dimes, quarters):
    cents = pennies
    cents += nickels*5
    cents += dimes*10
    cents += quarters*25
    return cents

def display_change(pennies, nickels, dimes, quarters):
    print ("You entered {} pennies {} nickels {} dimes and {} quarters".format(pennies, nickels, dimes, quarters))

def display_cents(cents):
    dollars = int(cents / 100) 
    cents = cents % 100
    print ("You have {} dollars and {} cents".format(dollars,cents))

if __name__ == "__main__":
    pennies = int(input("Enter the Number of pennies : "))
    nickels = int(input("Enter the Number of nickels : "))
    dimes = int(input("Enter the Number of dimes : "))
    quarters = int(input("Enter the Number of quarters : "))

    display_change(pennies, nickels, dimes, quarters)        

    cents = change_to_cents(pennies, nickels, dimes, quarters)
    display_cents(cents)

    if cents == 100:
        print("You Win")
    else:
        print("you fail")

Answer 2

这是最简单的答案：

penny = int(input('Enter the number of pennies: '))
nickel = int(input('Enter the number of nickels: '))
dime = int(input('Enter the number of dimes: '))
quarters = int(input('Enter the number of quarters: '))
PENNIES = 100
NICKELS = 20
DIMES = 10
QUARTERS = 4
dollar = (penny / PENNIES) + (nickel / NICKELS) + (dime / DIMES) + (quarters / QUARTERS)
if dollar == 1:
    print("Congratulations! You've entered one dollar!")
elif dollar > 1:
    print("Sorry! You've entered more than one dollar")
else:
    print("Sorry! You've entered less than one dollar")

当我输入输出时，我没有得到正确的结果

2 个答案: