我可以使用PHPUnit模拟接口实现吗?

时间:2013-09-24 04:19:43

标签: php interface mocking phpunit

我有一个我想要模拟的界面。我知道我可以模拟该接口的实现,但有没有办法只是模拟接口?

<?php
require __DIR__ . '/../vendor/autoload.php';

use My\Http\IClient as IHttpClient;  // The interface
use My\SomethingElse\Client as SomethingElseClient;


class SomethingElseClientTest extends PHPUnit_Framework_TestCase {
  public function testPost() {
    $url = 'some_url';
    $http_client = $this->getMockBuilder('Cpm\Http\IClient');
    $something_else = new SomethingElseClient($http_client, $url);
  }
}

我得到的是:

1) SomethingElseTest::testPost
Argument 1 passed to Cpm\SomethingElse\Client::__construct() must be an instance of
My\Http\IClient, instance of PHPUnit_Framework_MockObject_MockBuilder given, called in
$PATH_TO_PHP_TEST_FILE on line $NUMBER and defined

有趣的是,PHPUnit, mocked interfaces, and instanceof表明这可行。

3 个答案:

答案 0 :(得分:43)

而不是

$http_client = $this->getMockBuilder(Cpm\Http\IClient::class);

使用

$http_client = $this->getMock(Cpm\Http\IClient::class);

$http_client = $this->getMockBuilder(Cpm\Http\IClient::class)->getMock();

完全有效!

答案 1 :(得分:12)

以下适用于我:

$myMockObj = $this->createMock(MyInterface::class);

答案 2 :(得分:0)

$http_client = $this->getMockBuilder(Cpm\Http\IClient::class)
                    ->setMockClassName('SomeClassName')
                    ->getMock();

在某些情况下, setMockClassName()可用于解决此问题。