如何模拟其他模拟的属性？

Question

有人知道我如何模拟模拟的属性吗？

我下面的存储库需要一个ApiClient实例，并在其属性上调用一个方法：

<?php

class PaymentRepository
{
    public function __construct(ApiClient $apiClient)
    {
        $this->apiClient = $apiClient;
    }

    public function create()
    {
        return $this->apiClient->payments->create('args');
    }
}

我可以模拟ApiClient的实例并将其注入到PaymentRepository中，但是如何设置对其属性payments调用的方法的期望呢？

在模拟属性上设置新模拟似乎无效：

<?php

class PaymentRepositoryTest
{
    public function test_it_can_create_payments()
    {
        $apiClient = Mockery::mock(ApiClient::class);
        $paymentsEndpoint = M::mock(PaymentsEndpoint::class);
        $paymentsEndpoint->shouldReceive('create')
            ->with('args')
            ->once()
            ->andReturn(true);
        $apiClient->payments = $paymentsEndpoint;

        $payments = new PaymentRepository($apiClient);

        $this->assertTrue($payments->create());
    }
}

但是我得到了错误：

Error : Call to a member function create() on null

我也尝试过模拟，就像可以模拟方法链一样，但是Mockery仅支持链接方法。

<?php

class PaymentRepositoryTest
{
    public function test_it_can_create_payments()
    {
        $apiClient = Mockery::mock(ApiClient::class);
        $apiClient->shouldReceive('payments->create')
            ->with('args')
            ->once()
            ->andReturn(true);

        $payments = new PaymentRepository($apiClient);

        $this->assertTrue($payments->create());
    }
}

我该如何解决？我该如何设置对模拟财产的期望？