Question

我怎样才能在c＃中这样做？我有GUI和工作线程，我必须传递数组或能够从工作数组访问数组？！

Thread t = new Thread (delegate() { DoWork (double[,] data); });
t.Start();


static void DoWork (double[,] data) { do some work...; }

Answer 1

使用参数化线程委托（ParameterisedThreadStart）：

Thread t = new Thread(o =>
  {
    double[,] data = (double[,])o;
    DoWork(data);
  });

t.Start(myData);

编辑：或正如Paul在评论中建议的那样，通过闭包抓取myData：

Thread t = new Thread(() => DoWork(myData));
t.Start();

Answer 2

所有线程委托都接受一个对象。传递数组，然后在工人中投射：

double[,] myarray = ...;
ThreadPool.QueueUserWorkItem(state=>{
  double[,] arrayArg = (double[,])state;
  DoWork(arrayArg);
}, myarray);

ThreadStart有类似的论点。确保在工作线控制下的UI线程中不触摸数组...

Answer 3

来自MSDN：

class Test
{
    static void Main() 
    {
        Work threadWork = new Work(yourdata);
        Thread newThread = 
            new Thread(new ThreadStart(threadWork.DoWork));
        newThread.Start();
    }
}

class Work 
{
    private double[,] myData;
    public Work(double[,] data) {
        myData = data;
    }

    public void DoWork() { /* use myData */ }
}

如何将多维数组作为参数传递给C＃中的工作线程？

3 个答案: