当我执行此代码时,它会在控制台中出现错误,如此
Uncaught NotSupportedError: The implementation did not support the requested type of object or operation.
(anonymous function)
我的代码是:
<!DOCTYPE html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="description" content="Get multiple video streams on one page. Adapted from code by Muaz Khan">
<title>Video Camera List</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js" ></script>
<style type="text/css" media="screen">
video {
border:1px solid gray;
}
</style>
</head>
<body>
<script>
// alert('Hiii');
if (!MediaStreamTrack) document.body.innerHTML = '<h1>Incompatible Browser Detected. Try <strong style="color:red;">Chrome Canary</strong> instead.</h1>';
var videoSources = [];
MediaStreamTrack.getSources(function(media_sources)
{
console.log(media_sources);
media_sources.forEach(function(media_source){
if (media_source.kind === 'video') {
videoSources.push(media_source);
}
});
getMediaSource(videoSources);
});
var get_and_show_media = function(id) {
var constraints = {};
constraints.video = {
optional: [{ sourceId: id}]
};
navigator.webkitGetUserMedia(constraints, function(stream) {
console.log('webkitGetUserMedia');
console.log(constraints);
console.log(stream);
var mediaElement = document.createElement('video');
mediaElement.src = window.URL.createObjectURL(stream);
document.body.appendChild(mediaElement);
mediaElement.controls = true;
mediaElement.play();
}, function (e) {
document.body.appendChild(document.createElement('hr'));
var strong = document.createElement('strong');
strong.innerHTML = JSON.stringify(e);
document.body.appendChild(strong);
});
};
var getMediaSource = function(media) {
console.log(media);
media.forEach(function(media_source) {
if (!media_source) return;
if (media_source.kind === 'video') {
// add buttons for each media item
var button = $('<input/>', {id: media_source.id, value:media_source.id, type:'submit'});
$("body").append(button);
// show video on click
$(document).on("click", "#"+media_source.id, function(e){
console.log(e);
console.log(media_source.id);
get_and_show_media(media_source.id);
});
}
});
}
</script>
</body>
</html>
答案 0 :(得分:1)
试试这个......
在Google Chrome上输入 chrome:// flags / 。
启用WebRTC设备枚举,并启用getUserMedia。