我有一个包含多个字符串(文本)变量的文件,其中每个响应者为每个变量写了一两句话。我希望能够找到每个单词组合的频率(即“性能”与“性能”发生的频率)。 到目前为止我的代码是:
#Setting up the data file
data.text <- scan("C:/temp/tester.csv", what="char", sep="\n")
#Change everything to lower text
data.text <- tolower(data.text)
#Split the strings into separate words
data.words.list <- strsplit(data.text, "\\W+", perl=TRUE)
data.words.vector <- unlist(data.words.list)
#List each word and frequency
data.freq.list <- table(data.words.vector)
这给了我一个每个单词的列表以及它在字符串变量中出现的频率。现在我想看看每两个单词组合的频率。这可能吗?
谢谢!
字符串数据的示例:
ID Reason_for_Dissatisfaction Reason_for_Likelihood_to_Switch
1 "not happy with the service" "better value at other place"
2 "poor customer service" "tired of same old thing"
3 "they are overchanging me" "bad service"
答案 0 :(得分:1)
我不确定这是否是你的意思,而不是分裂每两个单词的边界(我发现尝试和正则表达的痛苦)你可以使用可靠的head
将每两个单词粘贴在一起和tails
滑动技巧......
# How I read your data
df <- read.table( text = 'ID Reason_for_Dissatisfaction Reason_for_Likelihood_to_Switch
1 "not happy with the service" "better value at other place"
2 "poor customer service" "tired of same old thing"
3 "they are overchanging me" "bad service"
' , h = TRUE , stringsAsFactors = FALSE )
# Split to words
wlist <- sapply( df[,-1] , strsplit , split = "\\W+", perl=TRUE)
# Paste word pairs together
outl <- sapply( wlist , function(x) paste( head(x,-1) , tail(x,-1) , sep = " ") )
# Table as per usual
table(unlist( outl ) )
are overchanging at other bad service better value customer service
1 1 1 1 1
happy with not happy of same old thing other place
1 1 1 1 1
overchanging me poor customer same old the service they are
1 1 1 1 1
tired of value at with the
1 1 1