Question

我需要将一列相加并除以另一列中的不同值

Column A           Column B
10                  James
20                  Phill
02                  James
10                  Bill
23                  Bill
14                  James

我的答案需要是A栏（79）除以不同的James（3），PHILL（1），BILL（2）

的总和

我的答案应该是：

James  26.333
Phil   79
Bill   39.5

我试过了：

select sum(column A)/distinct (column B)

Answer 1

按名称汇总金额列和组。

SELECT Name，SUM（Amount）As Amt FROM TableName GROUP BY Name

我的结果：

Name    Amt
Bill    33
James   26
Phill   20

您的问题已更改。我会更新答案......

SELECT (SELECT SUM(Amount) FROM TableName) / COUNT(Name) AS CalcAmount, Name
FROM TableName GROUP BY Name

结果：

CalcAmount  Name
39  Bill
26  James
79  Phill

Answer 2

select t1.sum_number/ count(t2.name), t2.name
from (
  select sum(number) as sum_number
  from t) as t1
join t as t2
join t as t3
  on t2.name = t3.name
  and t2.number = t3.number
group by t2.name

你可以摆弄它here

Answer 3

您可以使用窗口函数执行此操作：

select columnB,
       sum(sum(columnA)) over ()) / count(columnB) as YourAverage
from t
group by columnB;

Here是SQL小提琴。

Answer 4

试试此代码

SELECT C2, MAX(A.SUMC1)/COUNT(C2) CalcAmount
FROM TableA,
(SELECT SUM(C1) SUMC1 FROM TableA) A
GROUP BY C2

它有效，我在SQLFiddle http://sqlfiddle.com/#!3/54794/6/0

中查看

Answer 5

试试这个，假如说：表名=测试，列A =销售，列B =名称

     SELECT a.name, 
     (SELECT SUM(b.sales) / COUNT(a.NAME) FROM test AS b)
     FROM test AS a
     GROUP BY NAME

Answer 6

当您的DBMS支持“窗口功能”时，您可以执行以下操作：

SELECT ColB, CAST(SUM(SumA) OVER () AS FLOAT)/cnt CalcAmount
FROM
 (
   SELECT
      ColB,
      SUM(ColA) AS SumA, 
      COUNT(*) AS cnt
   FROM TableA
   GROUP BY ColB
 ) AS dt

如果ColA是INTEGER，则需要CAST（SUM（SumA）OVER（）AS FLOAT / DECIMAL）以避免截断结果

对列进行求和，并将不同的项除以另一个字段

6 个答案: