Question

我正在尝试制作一个获得学生姓名和成绩的计划。 e。当“退出”是类型时我有退出的功能，我想用名称粘贴结果，例如说： lucius F等。

我解决了最重要的部分，但我没有退出，数据更难。

  #include <conio.h>
  #include <stdio.h>
        int main()
     {
     int grade;
     char name;
       looperdo:
     printf("\n \nenter student name :");
     scanf("%s",& name);
     printf(" enter estudent  score:");
     scanf("%d",&grade);
     if(grade>=0 && grade <=49)
     printf("grade=F ");
     else 
     if(grade>=50&& grade <=59)
     printf(" grade=P ");
     if(grade >=60 && grade<=69)
     printf(" grade=C");
     else
     if(grade >=70 && grade <=79)
     printf(" grade=D ");
     if(grade >=80 && grade<=100)
     printf(" grade=HD ,");
     if (grade >100 || grade <0)
     printf ("out of range , type form 0 to 100.");

     goto looperdo;

    return 0;
     }

Answer 1

请勿使用goto

执行while循环：

  #include <stdio.h>
  #include <string.h>
  int main()
  {
     int grade;
     char name[128];
       do{
         printf("\n \nenter student name :");
         scanf("%s",&name);

         if(strcmp(name,"quit") == 0){break;} // This part is if you want to quit as soon as quit was printed

         printf(" enter estudent  score:");
         scanf("%d",&grade);

         printf("%s - ", name);//This prints the student's name

         if(grade>=0 && grade <=49)
         printf("grade=F ");
         else 
         if(grade>=50&& grade <=59)
         printf(" grade=P ");
         if(grade >=60 && grade<=69)
         printf(" grade=C");
         else
         if(grade >=70 && grade <=79)
         printf(" grade=D ");
         if(grade >=80 && grade<=100)
         printf(" grade=HD ,");
         if (grade >100 || grade <0)
         printf ("out of range , type form 0 to 100.");


     }while(name != "quit");

    return 0;
  }

坚持数据并创建退出功能

1 个答案: