Question

我对编程很新，我正在为我的妹妹创建一个小游戏......

我有一个while循环，我希望有一个选项可以退出游戏，但我所知道的退出技术似乎都不起作用：

#main game:
while 1:
    input_event_1 = gui.buttonbox(
        msg = 'Hello, what would you like to do with your Potato Head?',
        title = 'Main Screen',
        choices = ('Check Stats', 'Feed', 'Exercise', 'Teach', 'Play', 'Go to Doctor', 'Change Favourite Thing', 'Get New Toy', 'Quit'))
    if input_event_1 == 'Check Stats':
        myPotatoHead.check_p_h_stats()
    if input_event_1 == 'Change Favourite Thing':
        myPotatoHead.change_favourite_thing()
    if input_quit == 'Quit':
        input_quit = gui.ynbox(
        msg = 'Are you sure you want to quit?',
        title = 'Confirm quit',
        choices = ('Quit', 'Cancel'))
        if input_event_quit == 'Quit':
            sys.exit(1)

感谢任何帮助。

由于

- - - - - - - - UPDATE

感谢您的建议，但它仍然无效：

这是更新后的代码：

#import the required modules:
import easygui as gui
import os


#-----CLASS-----------------------------------
#Class:
class PotatoHead:

#Atributes:
    def __init__(self):
        self.data = game_data
        self.first_name = self.data[0]
        self.last_name = self.data[1]
        self.gender = self.data[2]
        self.colour = self.data[3]
        self.fav_thing = self.data[4]
        self.toys = []
        self.toys.append(self.data[5])
        self.age = '0.0'
        self.hunger = '0.0'
        self.health = '0.0'
        self.fitness = '0.0'
        self.education = '0.0'
        self.happiness = '0.0'
        self.tiredness = '0.0'

    def check_p_h_stats(self):
        self.toys_string = str(self.toys)
        gui.msgbox(
            msg = '''
Name: ''' + self.first_name + ' ' + self.last_name + '''
Gender: ''' + self.gender + '''
Colour: ''' + self.colour + '''
Favourite Thing: ''' + self.colour + '''
Toys:''' + self.toys_string + '''
Age: ''' + self.age + '''
Hunger: ''' + self.hunger + '''
Health: ''' + self.health + '''
Fitness: ''' + self.fitness + '''
Education: ''' + self.education + '''
Happiness: ''' + self.happiness + '''
Tiredness: ''' + self.tiredness + '''
''',
            title = 'Potato Head Stats',
            ok_button = 'Continue')

    def change_favourite_thing(self):
        new_fav_thing = gui.enterbox(
            msg = 'Enter the new favourite thing:',
            title = 'Change Favourite Thing',
            default = 'Type Here')
        self.fav_thing = new_fav_thing

#Methods:
#-----MAIN PROGRAM----------------------------
#set up game:
image = 'nest.gif'
game_choice = gui.ynbox(
    msg = """Would you like to start a new game,
or load a previously saved one?""",
    title = 'Start/Load Game',
    choices = ('New Game', 'Load Game'),
    image = image)
if game_choice == 1:
    fieldNames = ['First Name', 'Last Name', 'Gender', 'Colour', 'Favourite Thing',     'First Toy']
    new_p_head_data = []
    new_p_head_data = gui.multenterbox(
        msg = 'Fill in the starting information about your Potato Head:',
        title = 'New Game',
        fields = fieldNames,
        values = ('', '', 'Male/Female', 'Red, Green, Blue, Yellow, White, Black', '',     'Choose either Rattle, Pacifier, Teddy, Doll, or Soft Ball'))
    game_data = new_p_head_data
else:
    gui.msgbox('This function is not yet supported, please start again...')

myPotatoHead = PotatoHead()

#main game:
while 1:
    input_event_1 = gui.buttonbox(
        msg = 'Hello, what would you like to do with your Potato Head?',
        title = 'Main Screen',
        choices = ('Check Stats', 'Feed', 'Exercise', 'Teach', 'Play', 'Go to Doctor', 'Change Favourite Thing', 'Get New Toy', 'Quit'))
    if input_event_1 == 'Check Stats':
        myPotatoHead.check_p_h_stats()
    elif input_event_1 == 'Change Favourite Thing':
        myPotatoHead.change_favourite_thing()
    elif input_event_1 == 'Quit':
        input_quit = gui.ynbox(
            msg = 'Are you sure you want to quit?',
            title = 'Confirm quit',
            choices = ('Quit', 'Cancel'))
        if input_quit == 'Quit':
            sys.exit(1)

使用PYthon 2.5.4 for Mac 并使用Easygui 0.83

再次感谢任何建议

Answer 1

我认为这是你的问题：

if input_quit == 'Quit':
        input_quit = gui.ynbox(
        msg = 'Are you sure you want to quit?',

应该是

if input_event_1 == 'Quit':
        input_quit = gui.ynbox(
        msg = 'Are you sure you want to quit?',

编辑：根据EasyGui教程，它仍然不起作用的原因是ynbox返回0或1，而不是选项的字符串值。所以改为

    elif input_event_1 == 'Quit':
        input_quit = gui.ynbox(
            msg = 'Are you sure you want to quit?',
            title = 'Confirm quit',
            choices = ('Quit', 'Cancel'))
        if input_quit == 1:
            sys.exit(1)

Answer 2

我想也许是你的代码

 if input_quit == 'Quit':

应该是

 if input_event_1 == 'Quit':

就像你的其他支票一样？我不熟悉buttonbox那件事，但是这张支票和其他支票之间的差异立即引起了震动并跳到眼前......

编辑：啊，发现它，它来自easygui（提到你正在使用的框架会有所帮助！ - ） - 是的，它返回与按钮相关的字符串，所以我上面提出的改变绝对是关键点。

此外，将第一个之后的所有if input_event_1更改为elif input_event_1（因为它不能等于多个字符串，为什么一旦找到一个字符串就继续检查<强>是相等？ - ），虽然不是绝对必要的，但是会有所改善。

Answer 3

这种方式更优雅：

she_wants_to_play = true
while she_wants_to_play:
    ask input
    if input == quit:
        she_wants_to_play = false

所以你很好地退出了while循环，而不是以10000吨的重量击中系统。

Answer 4

几个检查站

您导入了sys？
if input_event_quit == 'Quit':应该是input_quit == 'Quit':

在Python中启用退出功能的问题

4 个答案: