Question

我真的是Python的新手。现在，我正在做一个涉及创建2D坐标列表的项目。坐标应均匀放置，使用方格（10 * 10），如（0,0）（0,1）（0,2）（0,3）......（0,10）（1,0））（1,2）（1,3）...（2,0）（2,1）（2,2）...（10,10）。

这是我的代码：

coordinate = []
x = 0
y = 0
while y < 10:
    while x < 10:
        coordinate.append((x,y))
        x += 1
    coordinate.append((x,y))
    y += 1
print(coordinate)

但我只能得到：[（0,0），（1,0），（2,0），（3,0），（4,0），（5,0），（6,0）），（7,0），（8,0），（9,0），（10,0），（10,1），（10,2），（10,3），（10,4），（10,5），（10,6），（10,7），（10,8），（10,9）]

如何重写代码以获取所有要点？

Answer 1

通常使用几个for循环来实现这一目标：

coordinates = []

for x in range(11):
  for y in range(11):
    coordinates.append((x, y))

通过将其展平为列表理解来简化这一点也很常见：

coordinates = [(x,y) for x in range(11) for y in range(11)]

Answer 2

from itertools import product

x = (0, 1, 2)

test = product(x, x)

结果：

>>> for ele in test:
...     print ele
... 
(0, 0)
(0, 1)
(0, 2)
(1, 0)
(1, 1)
(1, 2)
(2, 0)
(2, 1)
(2, 2)

请注意，test是一个生成器，因此您可能希望使用list(test)。

Answer 3

要真正回答您的问题，您在第一次运行x = 0..9后忘记将x重置为零：

coordinate = []

y = 0
while y < 10:
    x = 0
    while x < 10:
        coordinate.append((x,y))
        x += 1
    coordinate.append((x,y))
    y += 1
print(coordinate)

当然，请随意使用所有其他变体。

Answer 4

使用itertools.product：

>>> from itertools import product
>>> list(product(range(11), repeat=2))
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9), (0, 10), (1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (2, 10), (3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (3, 10), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (4, 10), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9), (5, 10), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6), (6, 7), (6, 8), (6, 9), (6, 10), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (7, 7), (7, 8), (7, 9), (7, 10), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (8, 8), (8, 9), (8, 10), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9), (10, 10)]

上面的代码相当于这个嵌套列表理解：

>>> [(x, y) for x in range(11) for y in range(11)]
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9), (0, 10), (1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (2, 10), (3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (3, 10), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (4, 10), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9), (5, 10), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6), (6, 7), (6, 8), (6, 9), (6, 10), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (7, 7), (7, 8), (7, 9), (7, 10), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (8, 8), (8, 9), (8, 10), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9), (10, 10)]

Answer 5

使用for循环。它允许你迭代称为“迭代器”的东西。 range是一个内置函数，它从其起始参数（第一个参数）返回一个迭代器。直至其结束参数（第二个参数）不包含。因此range(0,11)将返回0,1,2，...，10。

coordinate = []
for y in range(0, 11):
    for x in range(0, 11):
        coordinate.append((x,y))
print(coordinate)

有关Python中for循环的更多信息，请查看official wiki page。

使用Python创建2D坐标

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