Question

请有人告诉我如何使用基本的评分系统来使用此代码。

import random
print 'Welcome to Rock, paper, scissors!'
firstto=raw_input('How many points do you want to play before it ends? ')

playerscore=+0
compscore=+0

while True:
    choice = raw_input ('Press R for rock, press P for paper or press S for scissors, CAPITALS!!! ')

    opponent = random.choice(['rock', 'paper' ,'scissors' ])

    print 'Computer has chosen', opponent

    if choice == 'R' and opponent == "rock":
        print 'Tie'
        playerscore = playerscore+0
        compscore = compscore+0

    elif choice == 'P' and opponent == "paper":
        print 'Tie'
        playerscore = playerscore+0
        compscore = compscore+0

    elif choice == 'S' and opponent == "scissors":
        print 'Tie'
        playerscore = playerscore+0
        compscore = compscore+0

    elif choice == 'R' and opponent == "paper":
        print 'CPU Wins'
        playerscore = playerscore+0
        compscore = compscore+1

    elif choice == 'P' and opponent == "scissors":
        print 'CPU Wins'
        playerscore = playerscore+0
        compscore = compscore+1

    elif choice == 'S' and opponent == "rock":
        print 'CPU Wins'
        playerscore = playerscore+0
        compscore = compscore+1


    elif choice == 'P' and opponent == "rock":
            print 'You Win'
            playerscore = playerscore+1 
            compscore = compscore+0

    elif choice == 'S' and opponent == "paper":
            print 'You Win'
            playerscore = playerscore+1
            compscore = compscore+0

    elif choice == 'R' and opponent == "scissors":
            print 'You Win'
            playerscore = playerscore+1
            compscore = compscore+0


    print 'Player score is',playerscore
    print 'Computer score is',compscore

    if playerscore == firstto:
        'You won the game :)'
        exit()
    elif compscore == firstto:
        'You lost the game :('
        exit()

Answer 1

问题在于第3行的raw_input。raw_input总是返回一个字符串，而你需要的是一个int。如果您将第3行更改为：

firstto = int(raw_input('How many points do you want to play before it ends? '))

您的代码将有效。

要清理用户输入（以便在用户输入"hello"而不是5时代码不会崩溃），您可以将raw_input调用包装成{{1 }，try声明。

例如：

except

顺便说一下，你的代码陷入无限循环，因为你在使用valid_input = False # flag to keep track of whether the user's input is valid. while not valid_input: firstto_str = raw_input('How many points do you want to play before it ends? ') try: # try converting user input to integer firstto = int(firstto_str) valid_input = True except ValueError: # user input that cannot be coerced to an int -> raises ValueError. print "Invalid input, please enter an integer."提供的字符串与整数进行比较时。这将始终返回False：

raw_input

Answer 2

有很多方法可以优化此代码，但您的直接问题是raw_input和点的输入。这会返回一个字符串，而您需要一个int。用int()包裹它你会没事的。也就是说，直到某人输入了无法解析的内容。

firstto = int(raw_input('How many points do you want to play before it ends? '))

编辑：如果您有兴趣，我会尝试优化您的代码（不要走极端）：

import random

what_beats_what = [('R', 'S'), ('S', 'P'), ('P', 'R')]
choices = {'R': 'Rock', 'P': 'Paper', 'S': 'Scissors'}


def outcome(player_a, player_b):
    for scenario in what_beats_what:
        if player_a == scenario[0] and player_b == scenario[1]:
            return 'A'
        elif player_b == scenario[0] and player_a == scenario[1]:
            return 'B'


print 'Welcome to Rock, paper, scissors!'

score_to_win = 0

while True:
    try:
        score_to_win = int(raw_input('How many points do you want to play before it ends? '))
        if score_to_win > 0:
            break
    except ValueError:
        pass

    print 'Try again, with a positive integer.'

human_score = 0
cpu_score = 0

while human_score < score_to_win and cpu_score < score_to_win:
    human_choice = ''
    while True:
        human_choice = raw_input('Press R for rock, press P for paper or press S for scissors: ').upper()
        if human_choice in choices:
            break
        else:
            print 'Try again ...'

    cpu_choice = random.choice(choices.keys())
    print 'Computer has chosen: {0}'.format(choices[cpu_choice])

    result = outcome(human_choice, cpu_choice)

    if result == 'A':
        print "Human wins!"
        human_score += 1
    elif result == 'B':
        print "CPU wins!"
        cpu_score += 1
    else:
        print 'It is a tie!'

    print 'Human score is: {0}'.format(human_score)
    print 'CPU score is: {0}'.format(cpu_score)

print 'You won the game :)' if human_score > cpu_score else 'You lost the game :('

Answer 3

修改您的第一个raw_input值。你在那里得到一个字符串。

为了获得更好的结果，还要验证输入： - ）

while 1:
    firstto=raw_input('How many points do you want to play before it ends? ')
    if firstto.isdigit():
        firstto = int(firstto)
        break
    else:
        print "Invalid Input. Please try again"

这只接受带数字的字符串。即使有人将输入设为“5.0”，也会被忽略。

要更好地阅读raw_input，请点击here。要了解有关内置字符串方法的更多信息，请阅读here。

PS：这与问题无关。但有点建议。您的代码可以变得更简单。如果您正在学习，请将此代码保留为v0.1并根据您的进度进行更新。

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3 个答案: