Question

我正在制作一个模拟器，看看随机数生成器用来“滚动”蛇眼的次数。该程序只是重复

Not snake eyes yet :(

以下是代码：

import java.util.Random;

public class SnakeEyes {

public static void main(String[] args) {
    Random myRandom = new Random();
    int die1 = 0, tries = 0, die2 = 0;

    System.out.println("Welcome to SEO (Snake Eyes Operator)!");
    System.out.println("How many rolls will it take you to get to snake eyes! ");

    die1 = myRandom.nextInt(6) + 1;
    die2 = myRandom.nextInt(6) + 1;

    while (die1 + die2 != 2) {
        System.out.println("Not snake eyes yet :( ");
        tries = +1;

    }

    System.out.print("You have rolled snake eyes! ");
    System.out.print("Congratulations!  It only took you ");
    System.out.print(tries);
    System.out.print("!");

}

}

我认为这是一个开环的问题，但我不确定。谢谢！

Answer 1

使用while循环时，必须更新检查的值或循环永不停止。

您需要更新循环内的die1和die2值。

Answer 2

一旦这个while (die1 + die2 != 2)条件失败，它将进入无限循环，必须有一个条件来打破循环。试试这个（在10次迭代后会破坏循环）：

while (die1 + die2 != 2) {      
    System.out.println("Not snake eyes yet :( ");
    die1 = myRandom.nextInt(6) + 1;
    die2 = myRandom.nextInt(6) + 1;
    tries += 1;
    if(tries==10)
        break;
}

并将tries = +1;替换为tries += 1;

Answer 3

您需要在myRandom.nextInt(6) + 1;循环中指定<{1}} }，否则将通过反复检查相同的值进行迭代。

Answer 4

die1 + die2

没有改变，因此如果满足以下条件，循环将永远运行：

while (die1 + die2 != 2)

因此，您可能需要在while循环中添加逻辑以逻辑更新die1和/或die2的值。

Java Snake Eyes程序错误

4 个答案: