我有两张桌子:
表1:
------------------------------
|Country |Emp Level |Name|
|-----------|-----------|-----
|UK |Staff |A
|US |Admin Staff|B
|CA |Staff |C
|NL |Admin Staff|D
|MN |Intern |E
|IN |Staff |F
|UK |Staff |G
|US |Admin Staff|H
------------------------------
表2:
---------------------------------------------
|Level Guid |Level name |Country code |
|-----------|-----------|-------------------|
|101 |Admin Staff|UK |
|102 |Admin Staff|US |
|103 |Admin Staff|Global |
|105 |Staff |UK |
|106 |Staff |US |
|107 |Staff |Global |
|108 |Intern |UK |
|109 |Intern |US |
|110 |Intern |Global |
---------------------------------------------
结果应该是:
|Level ID |Level |Country| Count |
|105 |Staff |UK | 2 |
|102 |Admin Staff|US | 2 |
|107 |Staff |CA | 1 |
|103 |Admin Staff|NL | 1 |
|110 |Intern |MN | 1 |
|107 |Staff |IN | 1 |
在表2中,除美国以外的任何国家/地区都被视为全球。请注意,即使在表2中,除了美国,英国以外的所有国家都是全球性的,所以这些国家都是单独计算的。我已经尝试了查询,但它给了我错误More than 1 value returned in subquery
SELECT country,
emp - levels,
Count(emp - levels) count,
"LevelID"= CASE
WHEN (SELECT level_guid
FROM table_2 T
WHERE u.emp - levels = T.level_name
AND u.country IN ( 'UK', 'US' )) IS NOT NULL
THEN
(SELECT level_guid
FROM table_2 T
WHERE u.emp - levels = T.level_name
AND u.country NOT IN ( 'UK', 'US' ))
ELSE (SELECT level_guid
FROM [DPN_Reporting].dbo.taxonomytermset T
WHERE u.emp_levels = T.level_name
AND T.level_name = 'Global')
END
FROM table_1 u
WHERE emp - levels IS NOT NULL
AND emp - levels != ''
GROUP BY emp - levels,
country
ORDER BY Count(emp - levels) DESC
答案 0 :(得分:1)
试试这个
CASE
WHEN EXISTS(SELECT level_guid
FROM table_2 T
WHERE u.emp - levels = T.level_name
AND u.country IN ( 'UK', 'US' ))
THEN (SELECT MAX(level_guid)
FROM table_2 T
WHERE u.emp - levels = T.level_name
AND u.country NOT IN ( 'UK', 'US' ))
ELSE (SELECT MAX(level_guid)
FROM [DPN_Reporting].dbo.taxonomytermset T
WHERE u.emp_levels = T.level_name
AND T.level_name = 'Global')
END
答案 1 :(得分:1)
这里有两个查询:
SELECT T2.[Level Guid] [Level ID], T1.[Emp Level] Level, T1.Country, COUNT(*) Count
FROM Table1 T1
INNER JOIN Table2 T2 ON T1.[Emp Level] = T2.[Level name]
AND CASE T1.Country WHEN 'UK' THEN 'UK' WHEN 'US' THEN 'US' ELSE 'Global' END = T2.[Country code]
GROUP BY T2.[Level Guid], T1.[Emp Level], T1.Country
SQLFiddle:http://sqlfiddle.com/#!3/18e8f/8
和
SELECT DISTINCT T2.[Level Guid] [Level ID], T1.[Emp Level] Level, T1.Country,
(SELECT COUNT(*) FROM Table1 T3 WHERE T1.Country = T3.Country) Count
FROM Table1 T1
INNER JOIN Table2 T2 ON T1.[Emp Level] = T2.[Level name]
AND CASE T1.Country WHEN 'UK' THEN 'UK' WHEN 'US' THEN 'US' ELSE 'Global' END = T2.[Country code]
SQLFiddle:http://sqlfiddle.com/#!3/18e8f/7
Count
中的第一个将给出具有相同T2.[Level Guid], T1.[Emp Level], T1.Country
的人数。
Count
中的第二个将给出相同Country
的人数。请注意,我添加了DISTINCT以使结果与您相同。
我认为第二个作为查询是无用的,因为您丢失了例如2x UK Staff
和2x US Admin Staff
的信息。
作为建议,请不要在列名中添加空格!。
答案 2 :(得分:1)
这样的事可能适合你:
SELECT [Level Guid], [Level name], Country , COUNT(*) [Count]
FROM dbo.table_1 t1
LEFT JOIN dbo.table_2 t2 ON t2.[Country code] = CASE WHEN t1.Country IN ('UK','US') THEN t1.Country ELSE 'Global' END
AND t1.[Emp Level] = t2.[Level name]
GROUP BY [Level Guid], [Level name], Country
ORDER BY COUNT(*) DESC
<强> SQLFiddle DEMO 强>