Question

跟进我之前的问题

SQL Show all items that are on hire before and up until a certain date

我现在只想在设定的变量期间计算出租的日子。

我使用

计算出工具出租的天数

   ,(CASE WHEN off_hire = '21121231'
         THEN datediff(DAY, on_hire, GETDATE())
         ELSE datediff(DAY, on_hire, offhire)+1
    END) AS 'DAYS_OF_RENTAL'

21121231是工具仍在使用的日期。

我正在努力计算出仅使用

在JAN租用的天数

   ,(CASE WHEN (on_hire > @startdate) AND off_hire > @end_date
         THEN datediff(DAY, @startdate, @enddate )
         ELSE datediff(DAY, on_hire, off_hire)+1
    END) AS 'CALC_DAYS_ON_HIRE'

这显然不起作用，但这是我此刻一直在尝试的路线。

示例数据

tool      on_hire    off_hire
tool 1    02/01/2016 15/01/2016
tool 2    16/12/2015 16/01/2016
tool 3    05/01/2016 20/02/2016

我有一个变量set @startdate = 20160101和@enddate = 20160131

非常感谢任何帮助，我仍在学习，但到达那里： - ）

干杯

Answer 1

这样的东西？

declare @t table (id int, tool  varchar(10),    on_hire date,    off_hire date);
insert into @t values
(1,1,'2016-01-01','2016-01-10'),
(2,1,'2016-01-15','2016-01-20'),
(3,2,'2015-12-01','2016-01-10'),
(4,3,'2016-01-20','2016-02-10'),
(5,4,'2015-01-01','2017-01-10')


select tool,  sum(datediff(d,on_hire,off_hire)) + 1 dayshired
from
(
select tool,
        case 
            when on_hire < '2016-01-01' then '2016-01-01'
            else on_hire 
        end as on_hire,
        case 
            when off_hire > '2016-01-31' then '2016-01-31'
            else off_hire 
        end as off_hire         
from @t
) s
group by s.tool

Answer 2

我最终这样做了

   ,(CASE WHEN (on_hire < @startdate) AND off_hire > @enddate
         THEN datediff(DAY, @startdate, @enddate )+1

         WHEN (on_hire < @startdate) AND off_hire < @enddate
         THEN datediff(DAY, @startdate, off_hire)+1

         WHEN (on_hire > @startdate) AND off_hire > @enddate
         THEN datediff(DAY, on_hire, @enddate )

          WHEN (on_hire > @startdate) AND off_hire < @enddate
         THEN datediff(DAY, on_hire, off_hire )

    END) AS 'CALC_DAYS_ON_HIRE'

计算JAN

2 个答案: