我想做一个可以编辑文件的应用程序,比如打开一个txt文件,编辑它,保存并记住它的权限。我如何在活动中做到这一点?
谢谢。
答案 0 :(得分:1)
您可以像这样创建:
try {
final FileOutputStream fos = openFileOutput(fileName + extension, Context.MODE_PRIVATE);
fos.close();
} catch (FileNotFoundException e) {
Log.d(TAG, "File not found: " + e.getMessage());
} catch (IOException e) {
Log.d(TAG, "Error accessing file: " + e.getMessage());
}
接下来,您可以使用FileInputStream打开并编辑它。
您需要添加的权限:
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
希望它有用
答案 1 :(得分:1)
几天后,我有了下一个方法。
private static byte[] readFromFile(String filePath, int position, int size)
throws IOException {
RandomAccessFile file = new RandomAccessFile(filePath, "r");
file.seek(position);
byte[] bytes = new byte[size];
file.read(bytes);
file.close();
return bytes;
}
private void CopyFromAssetsToStorage(Context Context, String SourceFile, String DestinationFile) throws IOException {
InputStream IS = Context.getAssets().open(SourceFile);
OutputStream OS = new FileOutputStream(DestinationFile);
CopyStream(IS, OS);
OS.flush();
OS.close();
IS.close();
}
private void CopyStream(InputStream Input, OutputStream Output) throws IOException {
byte[] buffer = new byte[5120];
int length = Input.read(buffer);
while (length > 0) {
Output.write(buffer, 0, length);
length = Input.read(buffer);
}
}
private static void writeToFile(String filePath, String data, int position) throws IOException {
RandomAccessFile file = new RandomAccessFile(filePath, "rw");
file.seek(position);
file.write(data.getBytes());
file.close();
public static String readFileAsString(String filePath) throws IOException
{
String separator = System.getProperty("line.separator");
BufferedReader reader = new BufferedReader(new FileReader(filePath));
String line, results = "";
while( ( line = reader.readLine() ) != null)
{
results += line + separator;
}
reader.close();
return results;
}
哪,我今天用的。我希望这可以帮助别人。
很快见到你。