泛型无法做出正确的推论

时间:2013-09-08 19:13:50

标签: java generics compiler-errors

泛型类可能需要在其构造函数中使用匹配的泛型对象,如sscce

import java.util.ArrayList;
import java.util.List;

public class GenericsIssue<K> {
  public List<K> inner; 

  public GenericsIssue(List<K> input) {
    if(input == null) throw new NullPointerException();
    this.inner = input;
  }

  public K getFirst() {
    if(inner.isEmpty()) return null;
    return inner.get(0);
  }
  // Snip, code continues below

此外,工厂方法不会在其参数中指定泛型类型。例如,我们可能会这样做。请注意,没有任何警告,甚至没有&#34;未经检查的演员&#34;。

  // Code borrowed from Guava source
  public static <E> ArrayList<E> newArrayList() {
    return new ArrayList<E>();
  }
  // End Guava borrow      

  public static void main(String... args) {
    ArrayList<String> list = newArrayList();
    GenericsIssue<String> gi = new GenericsIssue<String>(list);
    System.out.println(gi.getFirst()); // (Always null. Not relevant.)
  }
}

但是,这个main几乎是一样的,但它不能在Eclipse或命令行中在JDK 7u25中编译。为什么呢?

  public static void main(String... args) {
    GenericsIssue<String> gi = new GenericsIssue<String>(newArrayList());
    System.out.println(gi.getFirst());
  }

这是编译器错误:

$ javac -d . -Xlint:unchecked GenericsIssue.java
GenericsIssue.java:23: error: constructor GenericsIssue in class GenericsIssue<K> cannot be applied to given types;
        GenericsIssue<String> gi = new GenericsIssue<String>(newArrayList());
                               ^
  required: List<String>
  found: ArrayList<Object>
  reason: actual argument ArrayList<Object> cannot be converted to List<String> by method invocation conversion
  where K is a type-variable:
    K extends Object declared in class GenericsIssue
1 error

1 个答案:

答案 0 :(得分:3)

泛型系统为limited in the inferences it can make,分配的处理方式与方法参数不同。您应该能够指定

new GenericsIssue<String>(GenericsIssue.<String>newArrayList());

(从理论上讲,这种推断应该是可能的,但这种分析水平还没有实现。)