嗨我有输入表单我已将虚拟数据添加到此表单中,由于某种原因,它将数据添加为数值,即“1”。我不确定我哪里出错了,在上传这些数据之前,我是否与我选择COUNT
电子邮件有关?
提前致谢
我的代码如下:
register.php
<div id="maincontentWrapper">
<div id="maincontent">
<div id="contentWrapper"></div><!--End registerWrapper -->
<article>
<p>Welcome to iManage, please login in below.</p>
</article>
<div id="loginform">
<div id="registerWrapper">
<form id="registerForm" method="POST" action="insert.php">
<h1><span class="log-in">Register</span></h1>
<p class="required"><span class="log-in">*Required Fields</span></p>
<div id="errorDiv"><?php
if (isset($_SESSION['error']) & isset($_SESSION['formAttempt'])) {
unset($_SESSION['formAttempt']);
print "Errors encountered<br/>\n";
foreach ($_SESSION['error'] as $error) {
print $error . "<br />\n";
} //end foreach
} //end if
?></div>
<p class="float">
<label for="password"><i class="icon-lock"></i>Name*</label>
<input type="text" id="name" name="name" placeholder="Name" class="showpassword">
<span class="errorFeedback errorSpan" id="nameError">Name is required</span>
</p>
<p class="float">
<label for="login"><i class="icon-user"></i>Username*</label>
<input type="text" id="username" name="username" placeholder="Username">
<span class="errorFeedback errorSpan" id="usernameError">Username is required</span>
</p>
<p class="float">
<label for="password"><i class="icon-lock"></i>Password*</label>
<input type="password" id="password" name="password" placeholder="Password" class="showpassword">
<span class="errorFeedback errorSpan" id="passwordError">Password is required</span>
</p>
<p class="float">
<label for="password"><i class="icon-lock"></i>Verify Password*</label>
<input type="password" id="password2" name="password2" placeholder="Verify Password" class="showpassword">
<span class="errorFeedback errorSpan" id="password2Error">Passwords dont match</span>
</p>
<p class="float">
<label for="password"><i class="icon-lock"></i>Email*</label>
<input type="text" id="email" name="email" placeholder="Email" class="showpassword">
<span class="errorFeedback errorSpan" id="emailError">Email is required or you have not entered a valid email address</span>
</p>
<p class="clearfix">
<input type="submit" name="submit" value="Register"></form>
</p>
</div>
</div>
</div>
</div>
</div>
class.Users.php
<?php
include("connect/class.Connect.php");
class Users extends Database {
function preventaccess () {
if (!isset($_POST['submit'])) {
die(header("Location: register.php"));
}
}
function validate() {
$_SESSION['formAttempt'] = true;
if (isset($_SESSION['error'])) {
unset($_SESSION['error']);
}
$_SESSION['error'] = array();
$required = array("username","name","email","password","password2");
//Check required fields
foreach ($required as $requiredField) {
if (!isset($_POST[$requiredField]) || $_POST[$requiredField] == "") {
$_SESSION['error'][] = $requiredField . " is required.";
}
}
if (!filter_var($_POST['email'],FILTER_VALIDATE_EMAIL)) {
$_SESSION['error'][] = "Invalid e-mail address";
}
if ($_POST['password'] != $_POST['password2']) {
$_SESSION['error'][] = "Passwords don't match";
}
//final disposition
if (count($_SESSION['error']) > 0) {
die(header("Location: register.php"));
} else {
unset($_SESSION['formAttempt']);
}
}
public function insert() {
$result = $this->mysqli->prepare("SELECT COUNT(*) FROM users WHERE email=?");
$result->bind_param("s", $_POST['email']);
$result->execute();
$result->bind_result($email_count);
$result->fetch();//fecth
$result->close();
if ($email_count > 0) {
echo "email exisits! click here to try <a href='register'>again</a>";
} else {
//escape the POST data for added protection
$username = isset($_POST['username']);
$cryptedPassword = crypt($_POST['password']);
$password = $cryptedPassword;
$name = isset($_POST['name']);
$email = isset($_POST['email']);
$stmt = $this->mysqli->prepare("INSERT INTO users (username, password, name, email) VALUES (?, ?, ?, ?)");
//var_dump($this->mysqli->error);
$stmt->bind_param('ssss', $username, $password, $name, $email); // bind strings to the paramater
/* execute prepared statement */
$stmt->execute();
printf("%d Row inserted.\n", $stmt->affected_rows);
/* close statement and connection */
$stmt->close();
} // end email_count and insert to table
} // end function
} // End users class
$run = new Users();
$run->preventaccess();
$run->validate();
$run->insert();
?>
答案 0 :(得分:2)
你犯了一个小错误。你写过:
$username = isset($_POST['username']);
但我认为你真正想做的是:
$username = isset($_POST['username']) ? $_POST['username'] : null;
实际上,您本身并不存储用户名等,但是如果发送了这些值。然后将布尔值true
转换为数字1
。
要使其有效,您还必须更改$name
和$email
,因为您还在那里使用了isset
。