我使用的是Is There a JSON Parser for VB6 / VBA?中提到的解析器,但是我在获取嵌套数组的值时遇到了问题。 这是我的JSON字符串(来自Web服务的响应,我验证了它并且它是有效的JSON):
Dim stJsonResponse As String
stJsonResponse = {"stat":"ok","list":[{"url":["http://www.worldcat.org/oclc/69935068?referer=xid"],"publisher":"Tascabili Economici Newton","form":["BA"],"lang":"ita","city":"Milano","author":"Kahlil Gibran; org Tommaso Pisanti.","year":"1993","isbn":["9788879833172"],"title":"Aforismi sabbia e spuma","oclcnum":"69935068"]}]}
这是我到目前为止的代码:
Dim oJSON As New JSON
Dim oJSONParsed As Object
Set oJSONParsed = oJSON.parse(stJsonResponse)
For Each keyName In oJSONParsed.keys
Select Case keyName
Case "stat":
Select Case oJSONParsed(keyName)
Case "ok":
MsgBox "stat OK"
Case "unknownId":
MsgBox "the request identifier looks like a valid ISBN number and unknown to xISBN service"
Case "invalidId":
MsgBox "the request identifier is not a valid ISBN number"
Case Else
'Case "unknownField": 'the request field is not supported
'Case "unknownFormat": 'the request format is not supported
'Case "unknownLibrary": 'the request library is not supported
'Case "unknownMethod": 'the request method is not supported
'Case "overlimit": 'the request is throttled, only header is returned
'Case "invalidAffiliateId": 'invalid affiliate id
'Case "invalidHash": 'invalid hash (subscription only)
'Case "invalidToken": 'invalid access token (subscription only)
MsgBox "Errore irreversiblie, Case interno su 'stat'"
End Select
Case "list":
'Here I am stuck, I tried several options but I do not know how to proceed
'Here latest attempt
Dim temp As String
temp = ""
Dim colJSONArray As Collection
Set colJSONArray = oJSONParsed.Item("list")
For Each key In colJSONArray
'-------> How do I get the values here? <-------
temp = temp + "Key: " + key + " Value: " + colJSONArray.Item("key") + vbNewLine
Next
MsgBox temp
Case Else
MsgBox "Errore irreversiblie"
End Select
Next
代码colJSONArray.Item("key")
给出了错误Invalid procedure call or argument
代码print colJSONArray.Count
为我提供1
任何帮助表示赞赏。
编辑:愚蠢的我......无法在“”中写入密钥!
'colJSONArray.Item(1)'工作并给我一个字典...我会从这里移动。
答案 0 :(得分:0)
如果colJSONArray.Item(“key”)是集合你需要得到这个集合的第一个元素。
...
dim tmp
For Each key In colJSONArray
tmp = colJSONArray.Item("key")
temp = temp + "Key: " + key + " Value: " + tmp(Lbound(tmp)) + vbNewLine
next key
....