Question

使用此JSON对象：

{
  "date_price": [
    {
      "date": "Jan 2000",
      "price": 1394.46
    },
    {
      "date": "Feb 2000",
      "price": 1366.42
    },
    {
      "date": "Mar 2000",
      "price": 1498.58
    },
    {
      "date": "Apr 2000",
      "price": 1452.43
    }
  ]
}

我如何循环使用并将每对日期价格保存在一个简单的数组中，使用类似的东西，例如：

var transformation = [];

transformation.push({date: i, price: d})

因为这里的问题是在控制台中，当我打印JSON对象时，它说它们是数组内的对象，所以我不能使用forEach()循环

Answer 1

假设您已将JSON解析为对象......

var obj = JSON.parse(json);

... map数据。

注意：根据您对我的问题的回答，您需要一个嵌套的数组结构，而不是一个对象数组（正如您在问题中所要求的那样）。

ES5

var transformation = obj.date_price.map(function(el) {
  return [ el.date, el.price ];
});

ES6

var transformation = obj.date_price.map(el => [ el.date, el.price ]);

输出

[
  ["Jan 2000", 1394.46],
  ["Feb 2000", 1366.42],
  ["Mar 2000", 1498.58],
  ["Apr 2000", 1452.43]
]

DEMO

Answer 2

编辑：因为您已经将JSON作为对象，所以您只需要从中获取date_price属性。这是一个完全符合您需要的对象类型的数组......所以......

create table parties (
  party_id int primary key,
  type text not null check (...),
  individual_name text null,
  organization_name text null,

  check ( /* validate columns for given types */ )
);

create table shareholders (
  shareholder_party_id int references parties(party_id),
  organization_party_id int references parties(party_id),
  share decimal(...) not null,

  primary key (shareholder_party_id, organization_party_id),

  check (...)
);

insert into table parties values
(1, 'Individual', 'Alice', null),
(2, 'Individual', 'Bob', null)
(3, 'Organization', null, 'Alice and Bob Co.');

insert into shareholders values
(1, 3, 0.5), --Alice owns 50% of Alice and Bob Co.
(2, 3, 0.5); --Bob owns 50% of Alice and Bob Co.

insert into assets (asset_id, owner_id) values (1, 3); --Alice and Bob Co own Asset 1

或者...

var result = jsonObject.date_price; // THIS is your array here.

先前给出的答案，假设是JSON字符串......

只需使用此...

var result = jsonObject['date_price']; // THIS is your array here.

Answer 3

使用dependencies { compile fileTree(include: ['*.jar'], dir: 'libs') compile 'com.parse.bolts:bolts-android:1.+' compile 'com.parse:parse-android:1.+' compile 'com.android.support:appcompat-v7:23.2.0' compile 'com.android.support:recyclerview-v7:23.2.0' compile 'com.facebook.android:facebook-android-sdk:4.0.0' compile 'com.android.support:design:23.2.0' compile 'com.android.support:support-v4:23.2.0' }和JSON.parse函数的简单解决方案：

＆＃13;

Array.map

＆＃13;

Answer 4

您可以这样做：

var abc = {
 "date_price": [
{
  "date": "Jan 2000",
  "price": 1394.46
},
{
  "date": "Feb 2000",
  "price": 1366.42
},
{
  "date": "Mar 2000",
  "price": 1498.58
},
{
  "date": "Apr 2000",
  "price": 1452.43
}
]
}
var array = $.map(abc, function(value, index) {
    return [value];
});

https://jsfiddle.net/atg5m6ym/3271/

Answer 5

最简单的解决方案。它已经是您需要的格式。您只需要删除嵌套。

var obj = {
  "date_price": [
    {
      "date": "Jan 2000",
      "price": 1394.46
    },
    {
      "date": "Feb 2000",
      "price": 1366.42
    },
    {
      "date": "Mar 2000",
      "price": 1498.58
    },
    {
      "date": "Apr 2000",
      "price": 1452.43
    }
  ]
};

var array = obj['date_price'];

就是这样。

循环通过JSON嵌套数组

5 个答案: