Question

我有一个这样的存储过程：

ALTER procedure [dbo].[Driverperformance] 
    @Ecode nvarchar(50), 
    @startdate datetime,
    @enddate datetime
as 
begin 

    declare @date1 datetime = CONVERT(datetime, @startdate + ' 00:01:00.000', 120);
    declare @date2 datetime = CONVERT(datetime, @enddate + ' 23:23:59.000', 120);

    SELECT 
        e.Ecode,CAST(q.dtime AS DATE) as Date, 
        e.Ename, 
        count(q.Ecode) CntEcode ,
        count(DelEcode) CntDelEcode
    FROM EmployeeMaster_tbl e 
    inner JOIN Transaction_tbl q 
        ON e.Ecode = q.Ecode where q.Ecode=@Ecode
        and dtime between '' + @date1 +'' and ''+@date2+'' 
    group by 
        e.Ecode, 
        e.Ename, 
        CAST(q.dtime AS date) 
    ORDER BY CAST(q.dtime AS date)--e.Ecode DESC
end

但我没有得到正确的DelEcode计数，我的存储过程出了什么问题我正在检查这样的DelEcode计数：select * from Transaction_tbl，其中dtime＆gt; ='2013-09-03 00：00：00.000'和dtime＆lt; ='2013-09-03 23：59：59.000'和DelEcode ='E003'我得到35行，但在执行存储过程时我只得到23个CntDelEcode计数

Answer 1

如果要计算不同“DelEcode”的数量，请尝试计数（不同的DelEcode）。如果没有，您将计算具有非零DelEcode值的记录数。如果您执行连接，则计数将是笛卡尔积的结果，而不是不同DelEcode的数量。

Answer 2

我假设您使用SQL Server 2008或更高版本，因为代码中有CAST(... as date)

存储过程存在几个问题：

一种消除时间的奇怪方式（只是演员到目前为止）
BETWEEN语句，用于比较字符串而非日期，因为+''语句。
在您实际需要datetime

date

最简单的方法是像这样重写存储过程

ALTER procedure [dbo].[Driverperformance] 
    @Ecode nvarchar(50), 
    @startdate date,
    @enddate date
as 
begin 

    SELECT 
        e.Ecode,CAST(q.dtime AS DATE) as Date, 
        e.Ename, 
        count(q.Ecode) AS CntEcode ,
        count(DelEcode) AS CntDelEcode
    FROM EmployeeMaster_tbl e 
    inner JOIN Transaction_tbl q 
        ON e.Ecode = q.Ecode 
    where q.Ecode=@Ecode
        and @startdate <= dtime 
        and dtime < @enddate
    group by 
        e.Ecode, 
        e.Ename, 
        CAST(q.dtime AS date) 
    ORDER BY CAST(q.dtime AS date)--e.Ecode DESC
end

调用此存储过程并传递datetime值的代码不应该出现问题，因为时间部分将被截断。只有在以SQL Server无法从您的设置中识别的格式传递字符串文字而不是日期时，才会遇到问题

如果必须在存储过程的其他部分使用datetime参数，则可以进行简单的转换：

ALTER procedure [dbo].[Driverperformance] 
    @Ecode nvarchar(50), 
    @startdate datetime,
    @enddate datetime
as 
begin 

    declare @date1 date= cast(@startdate as date);
    declare @date2 date= cast(@enddate as date);

    SELECT 
        e.Ecode,CAST(q.dtime AS DATE) as Date, 
        e.Ename, 
        count(q.Ecode) AS CntEcode ,
        count(DelEcode) AS CntDelEcode
    FROM EmployeeMaster_tbl e 
    inner JOIN Transaction_tbl q 
        ON e.Ecode = q.Ecode 
    where q.Ecode=@Ecode
        and @date1 <= dtime 
        and dtime < @date2
    group by 
        e.Ecode, 
        e.Ename, 
        CAST(q.dtime AS date) 
    ORDER BY CAST(q.dtime AS date)--e.Ecode DESC
end

您还可以通过重新排序ORDER BY来摆脱GROUP BY声明。对结果进行分组，因此您可以使用GROUP BY CAST(q.dtime AS date) , e.Ecode, e.Ename按日期获取结果订单，Ecode和Ename

虽然取两列的结果没有显示出正确的结果

2 个答案: