我试图通过使用以下代码将每个站号复制24次:
stnid <- NULL
for (i in 1:24) {
stnid[i] <- rep(paste0("station",i),times=24)
}
> stnid
[1] "station1" "station2" "station3" "station4" "station5" "station6" "station7" "station8" "station9"
[10] "station10" "station11" "station12" "station13" "station14" "station15" "station16" "station17" "station18"
[19] "station19" "station20" "station21" "station22" "station23" "station24"
但是,我收到警告说:
> warnings()
Warning messages:
1: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
2: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
3: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
4: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
5: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
6: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
7: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
8: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
9: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
10: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
11: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
12: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
13: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
14: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
15: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
16: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
17: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
18: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
19: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
20: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
21: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
22: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
23: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
24: In stnid[i] <- rep(paste0("station", i), times = 24) :
number of items to replace is not a multiple of replacement length
有人能解释我在这里做错了什么吗?谢谢。
预期:
每个站从站1到站24各24次。
答案 0 :(得分:3)
这是你想要的吗?
rep(x = paste0("station", 1:24), times = 24)
或者,如果您更希望一起出现具有相同编号的电台:
rep(x = paste0("station", 1:24), each = 24)
答案 1 :(得分:1)
这将创建一个24元素列表,每个元素的元素都是24长度向量:
stnid <- list()
for (i in 1:24) {
stnid[[i]] <- rep(paste0("station",i),times=24)
}
stnid